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solniwko [45]
4 years ago
8

What is the first operation used in solving this equation 2x + 5 = 10

Mathematics
2 answers:
vovikov84 [41]4 years ago
8 0
Subtraction. you subtract 5 from both sides.
Zielflug [23.3K]4 years ago
8 0
Answer is subtraction.

First you would subtract 5 on both sides
2x= 5
Then divide by 2
X= 5/2
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3 years ago
Which equation is the slope-intercept form of the line that passes through (6, –11) and is parallel to the graph of y = –23x + 1
Finger [1]

Answer:

Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 .

Step-by-step explanation:

Given as :

The equation of one line

y = - 23 x + 12

∵ The equation of line in slope-intercept form is

y = m x + c

where m is the slope of line and c is y-intercept

Now, Compare given line with standard line equation

So, The slope of given line = m = - 23

Now, Again

Other line is passing through point (6 , - 11) and is parallel to given line

so, both the lines are parallel

For parallel line condition , Slope of both lines are equal

Let The slope of other line = M

So, M = m = - 23

Now, Equation of other line passing through point (6 , - 11) and slope - 23 in slope-point form

y - y_1 = M × (x -  x_1)

i.e y - ( - 11) = (- 23) × (x - 6)

Or, y + 11 = - 23 × x + 138

Or, y = - 23 x + 138- 11

i.e y = - 23 x + 127

So, The equation of other line  y = - 23 x + 127

Hence, Equation of other line passing through point (6 , - 11) and parallel to given line is  y = - 23 x + 127 . Answer

8 0
3 years ago
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