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ella [17]
3 years ago
6

Number 1 to 20 are placed in a bag without replacing the first number what is the probability that the first number drawn will b

e odd and second one will be even
Mathematics
1 answer:
SOVA2 [1]3 years ago
7 0
Are there answer choices? if not for some reason i am going with 25 percent because there are 20 numbers and 10 are even and 10 are odd so the probability to get 2 odds is about 25%
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A rectangular piece of land requires 157 1/2 meters of fencing. If the length is 30 m less than the width, find the dimensions.
oksano4ka [1.4K]
2L+2W=157.5
L=W-30
2(W-30)+2W=157.5
2W-60+2W=157.5
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4w=217.5
 W=54.4(.37 rounded to nearest tenth)
  L=24.4
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HELP <br> Please don’t answer if you don’t know it.
inysia [295]

Answer:

d=5

Step-by-step explanation:

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What is the gallon percentage of 96 ounces
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Well
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The Information Technology Department at a large university wishes to estimate the proportion of students living in the dormitor
nadya68 [22]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.05 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can use as an estimator for p \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.05}{1.96})^2}=384.16  

And rounded up we have that n=385

3 0
2 years ago
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