The emf induced in the coil is -5.65 V
<h3>Induced emf in coil</h3>
The induced emf in the coil is given by ε = -NΔΦ/Δt where
- ΔΦ = change in magnetic flux Φ₂ - Φ₁ where
- Φ₁ = initial magnetic flux = -58 Wb and
- Φ₂ = final magnetic flux = 38 Wb and and
- Δt = change in time = t₂ - t₁ where
- t₁ = initial time = 0 s and
- t₂ = final time = 34 sand
- N = number of loops of coil = 2
Since ε = -NΔΦ/Δt
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
Substituting the values of the variables into the equation, we have
ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)
ε = -2(38 Wb - (-58 Wb))/(34 s - 0 s)
ε = -2(38 Wb + 58 Wb)/(34 s - 0 s)
ε = -2(96 Wb)/34 s
ε = -192 Wb/34 s
ε = -5.65 Wb/s
ε = -5.65 V
So, the emf induced in the coil is -5.65 V
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brainly.com/question/13051297
Answer: conduction
Explanation:
Because you are physically touching the handle
Answer:
18,000 j
Explanation:
the lightbulb dissipates 5W of power
P = ΔE / Δt
rearrange to solve for energy
ΔE = PΔt
P = 5W
t = 1 hour = 60 minutes = 3600 seconds
ΔE = 5 * 3600
ΔE = 18000 J
Answer:
B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.
Explanation:
Impulse created by ball Y on ball X = 40 x 1/6 Ns
Ball X will also create impulse 40 / 6 on ball Y .
impulse = change in momentum .
impulse in Y = change in momentum in Y .
Initial momentum of Y = .5 x 5 = 2.5
Let final velocity of Y after collision be v in opposite direction .
change in momentum of Y = v - (-2.5 )
so,
v + 2.5 = 40 / 6 = 6.67
v = 4.17 m / s .
Option B is correct .
B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.
