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OLEGan [10]
3 years ago
8

Which statements did both Aristotle and Ptolemy assume? Check all that apply.

Physics
2 answers:
tensa zangetsu [6.8K]3 years ago
6 0

Bodies in space traveled in circles.

The planets revolved around the Earth.

Sav [38]3 years ago
3 0

Answer:

Bodies in space traveled in circles.

The planets revolved around the Earth.

Explanation:

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Quando aquecemos água em nossas casas, ao nível do mar, utilizando um recipiente aberto, sua temperatura nunca ultrapassa os 100
iren2701 [21]

Answer:

i dont speak spanish

Explanation:

4 0
3 years ago
A narrow beam of light from a laser travels through air (n = 1.00) and strikes the surface of the water (n = 1.33) in a lake at
Natalka [10]

Answer:

A) d = 11.8m

B) d = 4.293 m

Explanation:

A) We are told that the angle of incidence;θ_i = 70°.

Now, if refraction doesn't occur, the angle of the light continues to be 70° in the water relative to the normal. Thus;

tan 70° = d/4.3m

Where d is the distance from point B at which the laser beam would strike the lakebottom.

So,d = 4.3*tan70

d = 11.8m

B) Since the light is moving from air (n1=1.00) to water (n2=1.33), we can use Snell's law to find the angle of refraction(θ_r)

So,

n1*sinθ_i = n2*sinθ_r

Thus; sinθ_r = (n1*sinθ_i)/n2

sinθ_r = (1 * sin70)/1.33

sinθ_r = 0.7065

θ_r = sin^(-1)0.7065

θ_r = 44.95°

Thus; xonsidering refraction, distance from point B at which the laser beam strikes the lake-bottom is calculated from;

d = 4.3 tan44.95

d = 4.293 m

4 0
3 years ago
A wheel rotates at 24 revolutions every 3 minutes. This is equivalent to
mrs_skeptik [129]
8 revolutions every minute
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2 years ago
Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.320 mm wide. The diffraction pattern is observed
DanielleElmas [232]

Answer:

W = 10.28\ mm

Explanation:

Given,

Red light wavelength = 633 nm

width of slit = 0.320 mm

distance,d = 2.60 m

Condition of first maximum

a sin \theta_1 = m\lambda

\theta_1 =sin^{-1}(\dfrac{m\lambda}{a})

m = 1

\theta_1 =sin^{-1}(\dfrac{633\times 10^{-9}}{0.32\times 10^{-3}})

\theta_1 = 0.1133^\circ

Width of the first minima

y_1 = L tan \theta_1

y_1 = 2.60\times tan( 0.11331)

y_1 = 5.14 \ mm

Now, width of the central region

W = 2 y_1

W = 2\times 5.14

W = 10.28\ mm

8 0
3 years ago
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