Question

The magnetic flux through a coil of wire containing two loops changes at a constant rate from -58 wb to 38 wb in 0. 34 s. What is the emf induced in the coil?

Answer 1

The emf induced in the coil is -5.65 V

Induced emf in coil

The induced emf in the coil is given by ε = -NΔΦ/Δt where

• ΔΦ = change in magnetic flux Φ₂ - Φ₁ where
• Φ₁ = initial magnetic flux = -58 Wb and
• Φ₂ = final magnetic flux = 38 Wb and and
• Δt = change in time = t₂ - t₁ where
• t₁ = initial time = 0 s and
• t₂ = final time = 34 sand
• N = number of loops of coil = 2

Since ε = -NΔΦ/Δt

ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)

Substituting the values of the variables into the equation, we have

ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)

ε = -2(38 Wb - (-58 Wb))/(34 s - 0 s)

ε = -2(38 Wb + 58 Wb)/(34 s - 0 s)

ε = -2(96 Wb)/34 s

ε = -192 Wb/34 s

ε = -5.65 Wb/s

ε = -5.65 V

So, the emf induced in the coil is -5.65 V

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