Answer:
In guinea pigs, the gene for black fur, B, is dominant over the gene for white fur, b. Complete the Punnett square below to show the results of one possible cross between two guinea pigs with black fur.
BB X Bb = BB, Bb, BB, Bb
Explanation:
From the analogy shown, it is obvious that both parents are gene with black fur. During such crossing, the offspring are two homozygous dominant black fur and two heterozygous dominant black fur
Hello there.
<span>What type of symmetry is shown in this sponge?
</span><span>B. radial symmetry
</span>
Could u possibly give me any options or is it opionon based. let me know ill answer it in a jiffy:)
The first one is A.
The second one is B.
Hope this helped!
~Wolfe<3
