Answer:
Joe saved 68.25
Step-by-step explanation:
Subtract 6.85 from 80, you get 73.15
Subtract 5.50 from 73.15 and you get 67.65.
Subtract 21.40 from 67.65 and you get 46.25.
Add 22 to that amount, you get 68.25.
P.S
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<em><u>~Faker/Tosrel</u></em>
Answer:
( 3x - 2, 2x ± yx ) ± 1
Step-by-step explanation:
Answer:
Someone who walks 60 feet in 10 seconds
Step-by-step explanation:
It takes someone else 5 seconds to walk 25 feet.
25 feet x 2 is 50 feet.
5 seconds x 2 is 10 seconds.
That means that person is walking 50 feet per second, and 50<60.
I hope this helps!
Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
<h3>
How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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