If ages are normally distributed then using a significance level of 0.05 , we can claim that the population mean is greater than 24.
Given sample mean of 25 years , sample size of 16 ,standard deviation of 2 years.
We have to find whether the population average is greater than 24.
We have to use t test because n is less than 30. It is right tailed.
We have to first form Hypothesis.
:μ>24,
:μ<24.
t=X-μ/S/
t critical at 5% significance level and degree of freedom=15 (16-1)=1.7531
t=24-25/2/
=-1/0.5
=-2
Because 1.7531 is greater than -2 so we will accept the null hypothesis.
Hence we can say that the average of population is greater than 24.
Learn more about t test at brainly.com/question/6589776
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Answer:
t=5x=3049
Step-by-step explanation:
Answer:
Step-by-step explanation:
area of a circle=πr^2
=3.14*(73)^2
=3.14*5329
=16733.06 ft^2
Answer:
No, the sign won't change. The sign will only change if you multiply each side by -1.
Step-by-step explanation:
adding negative numbers also won't change the sign. We can see this because we are adding the same numbers
6<10
10<14
2<6
-6<-2
Answer: StartFraction negative 1 plus-or-minus StartRoot 21 EndRoot Over 2
Step-by-step explanation:
The given quadratic equation is expressed as
x² = 5 - x
Rearranging the equation to take the standard form of ax² + bx + c, it becomes
x² + x - 5 = 0
The general formula for solving quadratic equations is expressed as
x = [- b ± √(b² - 4ac)]/2a
From the equation given,
a = 1
b = 1
c = - 5
Therefore,
x = [- 1 ± √(1² - 4 × 1 × - 5)]/2 × 1
x = [- 1 ± √(1 - - 20)]/2
x = [- 1 ± √21]/2
x = (- 1 + √21)/2 or x = (- 1 - √21)/2
