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jarptica [38.1K]
4 years ago
12

How many grams of a solution that is 5.2% sucrose by mass are needed to obtain 18g of sucrose

Chemistry
1 answer:
kirill115 [55]4 years ago
3 0

Answer:

346.g of solution

Explanation:

In this case, if we have 5.2 % by mass it means that in <u>100 g of the solution we will have 5.2 g of glucose</u>. Therefore we can do the calculation:

<u>5.2 g of glucose = 100 g of solution</u>

18~g~of~glucose\frac{100~g~of~solution}{5.2~g~of~glucose}=346.15~g~of~solution

So, if we need 8 g of glucose we had to have 346.15 g of solution

This logic can work for all types of solutions. By mass (as in this case), by volume or mass/volume.

I hope it helps!

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Please help!! Why is the following Electron Configuration incorrect for Aluminium?
Margarita [4]

Answer:

3s^1 would be 3s^2

Explanation:

5 0
3 years ago
The value of ksp for silver sulfide, ag2s, is 8.00×10−51. calculate the solubility of ag2s in grams per liter.
Ivanshal [37]
When Ag₂S dissolves, it dissociates as follows;
Ag₂S ---> 2Ag⁺ + S²⁻
First we need to calculate molar solubility which gives the number of moles dissolved in 1 L of solution.
If molar solubility of Ag₂S is y, then molar solubility of Ag²⁺ and S²⁻ is 2y and y respectively.
ksp gives the solubility constant
ksp = [Ag⁺]²[S²⁻]
ksp = [2y]²[y]
4y³ = 8.00 x 10⁻⁵¹ 
y³ = 2 x 10⁻⁵¹
y = 1.26 x 10⁻¹⁷ mol/L
molar mass = 247.8 g/mol
solubility of Ag₂S = 1.26 x 10⁻¹⁷ mol/L x 247.8 g/mol = 3.12 x 10⁻¹⁵ g/L 
Solubility of Ag₂S = 3.12 x 10⁻¹⁵ g/L 
7 0
4 years ago
Read 2 more answers
I know how to solve it with D=M/V and M1V1 however the answer isn’t correct. Help me please
lara31 [8.8K]

Answer:

23.28 g of O2.

Explanation:

We'll begin by calculating the mass of hexane. This can obtain as follow:

Volume of hexane = 10 mL

Density of hexane = 0.66 g/mL

Mass of hexane =?

Density = mass /volume

0.66 = mass of hexane /10

Cross multiply

Mass of hexane = 0.66 x 10

Mass of hexane = 6.6 g

Next, we shall write the balanced equation for the reaction. This is given below:

2C6H14 + 19O2 —> 12CO2 + 14H2O

Next, we shall determine the masses of C6H14 and O2 that reacted from the balanced equation. This can be obtained as follow:

Molar mass of C6H14 = (12.01x6) + (1.008 x 14)

= 72.06 + 14.112

= 86.172 g/mol

Mass of C6H14 from the balanced equation = 2 x 86.172 = 172.344 g

Molar mass of O2 = 16x2 = 32 g/mol

Mass of O2 from the balanced equation = 19 x 32 = 608 g

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Finally, we shall determine the mass of O2 needed to react with 10 mL (i.e 6.6 g) of hexane, C6H14. This can be obtained as follow:

From the balanced equation above,

172.344 g of C6H14 reacted with 608 g of O2.

Therefore, 6.6 g of C6H14 will react with = (6.6 x 608)/172.344 = 23.28 g of O2.

Therefore, 23.28 g of O2 is needed for the reaction.

8 0
3 years ago
What type of solution do you have if you dissolve 20.2 g of potassium chlorate in 0.300 L
lara31 [8.8K]

solution of potassium chlorate,

K

C

I

O

3

, has 20 grams of the salt dissolved in 100 grams of water at 70 C. Approximately how many more grams of the salt can be added to the solution before reaching the saturation point?

4 0
2 years ago
If L = 5, then the magnetic quantum number "mL" can be equal to
Anit [1.1K]

b. -5, -4, -3, -2, -1, 0, +1, +2, +3, +4, +5

<h3>Further explanation</h3>

Each orbital in an atom consists of 4 quantum numbers  

n is the principal quantum number.  

l is the angular momentum / azimuthal quantum number  

ml, the magnetic quantum number  

ms, the electron-spin quantum number  

Value of n: positive integer  

value of l: s = 0, p = 1, d = 2, f = 3 , ..(n-1)

ml value: between -l to + l  

ms value: +1/2 or -1/2  

So for L=5, mL value : -5 to +5

6 0
3 years ago
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