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tester [92]
2 years ago
6

Write a balanced equation for the reactionbetween ammonia and sulfuric acid?​

Chemistry
1 answer:
Slav-nsk [51]2 years ago
8 0

Balanced equation for the reaction between ammonia and sulphuric acid is:

Explanation:

2NH3+H2SO4→(NH4)2SO4

I hope it'll help you...

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A closed flask contains gas at STP. If the temperature is raised to 400 K what will the pressure be in atm?
balandron [24]

Answer:

The answer is 1.5 atm

Explanation:

5 0
2 years ago
Select the correct answer. How does an atom become a positively charged ion? A. By gaining one or more electrons B. By gaining o
ser-zykov [4K]

C. By losing one or more electrons

6 0
3 years ago
Read 2 more answers
Hello,
nikitadnepr [17]

Answer:

a)\ 2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3\\b)\ Decomposition\ Reaction

Explanation:

<em>Ferrous Sulphate</em>(FeSO4)<em> is generally found as Lime-Green Crystals. On heating, these crystals almost immediately turn white-yellow. They then, break down to produce an anhydrous mixture of Sulphur Trioxide </em>(SO_3)<em>, Sulphur Dioxide </em>(SO_2)<em>  as well as Ferric Oxide </em>(Fe_2O_3)<em>.</em>

<em>We can hence, frame a skeletal equation of this reaction and try to balance it.</em>

<em>Hence,</em>

FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3

<em>Now,</em>

<em>a)In order to balance it through the 'Hit &Trial Method', we'll follow a series of </em><em>steps</em><em>:</em>

<em>1. First, lets compare the number of  Fe (Iron) atoms on the RHS and LHS. We find that, the no. of Fe Atoms on the RHS is twice the number of Fe Atoms on the LHS. We hence, add a co-effecient 2 beside </em>FeSO_4.

<em>2. Now, Iron atoms, Sulphur Atoms and Oxygen atoms occur 2, 2, 8 respectively on both the sides:</em>

<em> Hence, As all the other elements as well as iron, balance, we've arrived upon our Balanced Equation :</em>

<em> </em>2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3

<em>b) We know that, decomposition reactions are [generally] endothermic reactions in which Large Compounds </em><em>decompose </em><em>into smaller elements and compounds. Here, as Ferrous Sulphate </em><em>decomposes </em><em>into Sulphur Dioxide, Sulphur Trioxide and Ferric Oxide, the reaction that occurs here is </em><em>Decomposition Reaction.</em>

7 0
3 years ago
How many grams of K2Cr207 are in 250. mL of 0.500M of K2Cr207:
goldenfox [79]

<u>Analysing the Question:</u>

We are given a 250 mL solution of 0.5M K₂Cr₂O₇

Which means that we have:

0.5 Mole in 1L of the solution

0.125 moles in 250 mL of the solution      <em>[dividing both the numbers by 4]</em>

<em />

<u>Mass of K₂Cr₂O₇ in the given solution:</u>

Molar mass of K₂Cr₂O₇(Potassium Dichromate) = 194 g/mol

<em>we know that we have 0.125 moles in the 250 mL solution provided</em>

Mass = Number of moles * Molar mass

Mass = 0.125 * 194

Mass = 36.75 grams

7 0
3 years ago
What total volume of ozone measured at a pressure of 24.5 mmHg and a temperature of 232 K can be destroyed when all of the chlor
ddd [48]

Answer:

1.75272\ \text{m}^3

Explanation:

The breakdown reaction of ozone is as follows

CF_3Cl + UV \rightarrow CF_3 + Cl

Cl + O_3 \rightarrow ClO + O_2

O_3 + UV \rightarrow O_2 + O

ClO + O \rightarrow Cl + O_2

It can be seen that 2 moles of ozone is required in the complete cycle

So for 10 cycles, 20 moles of ozone is required

m = Mass of CF_3Cl = 15.5 g

M = Molar mass of CF_3Cl = 104.46 g/mol

P = Pressure = 24.5 mmHg

T = Temperature = 232 K

R = Gas constant = 62.363\ \text{L mmHg/K mol}

Number of moles is given by

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{15.5}{104.46}\\\Rightarrow n=0.1484\ \text{moles}

20\ \text{moles} = 20\times 0.1484 = 2.968\ \text{moles}

From ideal gas law we have

PV=nRT\\\Rightarrow V=\dfrac{nRT}{P}\\\Rightarrow V=\dfrac{2.968\times 62.363\times 232}{24.5}\\\Rightarrow V=1752.72\ \text{L}=1.75272\ \text{m}^3

For 20 cycles of the reaction the volume of the ozone is 1.75272\ \text{m}^3.

7 0
3 years ago
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