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Vesnalui [34]
3 years ago
6

how long does it take a car to accelerate from 3.4m/s to 20.9m/s if the average acceleration is 6.0m/s (squared).

Physics
1 answer:
Gre4nikov [31]3 years ago
4 0

Average acceleration is the ratio of the change in velocity to the time it takes for that change to occur:

a_{\mathrm{av}}=\dfrac{\Delta v}{\Delta t}

We want to find \Delta t:

6.0\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{20.9\,\frac{\mathrm m}{\mathrm s}-3.4\,\frac{\mathrm m}{\mathrm s}}{\Delta t}

\implies\Delta t=2.9\,\mathrm s

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Calculate the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal. Assume that the spe
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Answer:

the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal is 1835.16 .

Explanation:

We know, wavelength is expressed in terms of Kinetic Energy by :

\lambda=\dfrac{h}{\sqrt{2mE}}

Therefore , E=\dfrac{h^2}{2 \lambda^2 m}

It is given that both electron and proton have same wavelength.

Therefore,

E_e=\dfrac{h^2}{2 \lambda^2 m_e}   .... equation 1.

E_p=\dfrac{h^2}{2 \lambda^2 m_p}   .... equation 2.

Now, dividing equation 1 by 2 .

We get ,

\dfrac{E_e}{E_p}=\dfrac{\dfrac{h^2}{2 \lambda^2 m_e}}{\dfrac{h^2}{2 \lambda^2 m_p}}\\\\\\\dfrac{E_e}{E_p}=\dfrac{m_p}{m_e}

Putting value of mass of electron = 9.1\times 10^{-31}\ kg and mass of proton = 1.67\times 10^{-27}\ kg.

We get :

\dfrac{E_e}{E_p}=\dfrac{1.67\times 10^{-27}\ kg}{9.1\times 10^{-31}\ kg}=1835.16

Hence , this is the required solution.

4 0
4 years ago
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Suppose there was a star with a parallax angle of 1 arcsecond. How far away would it be? Select all that apply.
lesya692 [45]

Answer:

option E

Explanation:

given,                          

Parallax angle(d) = 1 arcsecond

using Parallax formula                  

      d = \dfrac{1}{p}

 p is the parsecs angle which is measured in 1 arcsecond

 d is the distance in parsec

now,                                            

      P = \dfrac{1}{d}

      P = \dfrac{1}{1}

      P = 1 \ parsec

we know,                                  

    1 parsec = 3.26 light year

hence, the answer will be option E

6 0
4 years ago
Since most people who are electrocuted don’t blow up, what kills them?
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8 0
4 years ago
A migrating bird flew across a lake at an average speed of 18 meters per second. Was the distance that the bird flew across the
Natasha_Volkova [10]

Answer:

It cannot be said with 100% guarantee.

Explanation:

Since bird is travelling with 18 meters per second, that means that it covers a distance of 18 meters in 1 second.

for part 1 we convert 20 minutes into seconds, thus, 20 * 60 = 1200 seconds.

Distance covered in 1200 seconds will be:

S = v * t (S is distance , v is speed, t is time)

18 * 1200 = 21600 meters = 21.6 Kilometers

If the bird took less than 20 minutes than distance covered would be less than 21.6 Kilometer which could be greater than or lesser than 21 Kilometers. On average we can say that the distance bird travelled will be less than 21 Kilometer. But it is not definite.

For part B convert 0.4 hours into seconds to find the distance it travelled.

0.4 * 60 * 60 = 1440 seconds

Distance covered will be

18 * 1440 = 25920 meters = 25.9 Kilo meters.

Again, if the bird takes less than 0.4 hours to cover the lake, the lake will be less than 25.9 kilometers long. This means that it could be greater than or lesser than 21 kilometers. It cannot be definitive

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3 years ago
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