What is the direction of the magnetic force on a singly ionized negative chlorine ion moving in this ocean current?
1 answer:
The ocean current the question talks about is the following:
"The Gulf Stream moves northward off the east coast of the United States at a speed of up to 3.5 m/s. Assume that the current<span> flows at this maximum speed and that the earth's field is 50 μT tipped 60° below horizontal. "
The situation is represented in the picture attached.
In order to find the direction of the magnetic force (Lorentz's force) you need to use the rule of the right hand: since the charge moving is negative, you need to place your thumb in the opposite direction of the velocity, while you need to place the other fingers in the same direction of the magnetic field. The magnetic force's direction will be perpendicular to your hand and the sense will be exiting the palm of your hand (and the sheet).
</span>
"The Gulf Stream moves northward off the east coast of the United States at a speed of up to 3.5 m/s. Assume that the current<span> flows at this maximum speed and that the earth's field is 50 μT tipped 60° below horizontal. "
The situation is represented in the picture attached.
In order to find the direction of the magnetic force (Lorentz's force) you need to use the rule of the right hand: since the charge moving is negative, you need to place your thumb in the opposite direction of the velocity, while you need to place the other fingers in the same direction of the magnetic field. The magnetic force's direction will be perpendicular to your hand and the sense will be exiting the palm of your hand (and the sheet).
</span>
You might be interested in
Speed of the block at the bottom of the incline: 5.42 m/s
The first part of the problem can be solved by using the law of conservation of energy. Since the ramp is frictionless, the initial gravitational potential energy of the block at the top of the ramp is converted into kinetic energy at the bottom:
(1)
where
m is the mass of the block
g = 9.8 m/s^2 is the acceleration of gravity
h is the initial height of the block
v is the speed of the block at the bottom
The initial height of the block is equal to the height of the ramp, so
(2)
where
L = 3.00 m is the length of the ramp
is the angle of the ramp
Substituting (2) into (1) and re-arranging the equation, we find the speed
Coefficient of kinetic friction between the floor and the block: 0.3
In the second part of the motion, the block is slowed down by friction along the flat surface. According to the work-energy theorem, the work done by friction is equal to the change in kinetic energy of the block:
where
W is the work done by friction
Kf is the final kinetic energy of the block, which is zero since the block comes to rest
is the initial kinetic energy of the block, where
m = 10.0 kg is the mass of the block
v = 5.42 m/s is its initial speed
Substituting into the equation, we find
and the work is negative, since the direction of the force of friction is opposite to the direction of motion of the block.
Now we can rewrite the work as the product between the force of friction and the displacement of the block:
where
is the coefficient of friction
d = 5.00 m is the displacement of the block
Solving for ,