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3 years ago

I don’t know what to do help me

Physics

1 answer:

kirill115 [55]3 years ago

4 0

Answer:

oooh thats hard

Explanation:

well i would probaly search the page number or anthing on the page that should help

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Explain the term "avalanche state"

vagabundo [1.1K]

Answer:

The downwind side of an obstacle such as a ridge. The addition of weight on top of a snowpack, usually from precipitation, wind drifting, or a person. An avalanche that releases from a point and spreads downhill collecting more snow - different from a slab avalanche. Also called a point-release or sluff.

Explanation:

5 0

3 years ago

A rod of length L is pivoted about its left end and has a force F applied perpendicular to the other end. The force F is now rem

timurjin [86]

Answer:

$F' = 4F$

Explanation:

When force applied to the end of the rod in perpendicular direction then net torque on the rod is given as

$\tau = L F sin90$

$\tau = LF$

Now another force is applied at mid point of the rod at an angle of 30 degree with the rod

so new value of torque is given as

$\tau = \frac{L}{2}F' sin\theta$

$LF = \frac{L}{2}F' sin30$

$LF = \frac{F'L}{4}$

so we have

$F' = 4F$

3 0

3 years ago

A sprinter reaches his maximum speed in 2.6 seconds from rest with constant acceleration. He then maintains that speed and finis

Delvig [45]

Answer: maximum speed vmax = 11.42m/s

Explanation:

Given that the sprinter maintained constant acceleration during the first 2.6 seconds.

a = vmax/ta .......1

The distance covered during the acceleration period is;

da = 0.5a(ta)^2 .....2

Substituting equation 1 to 2

da = 0.5(vmax/ta)(ta)^2 = 0.5vmax(ta) .....3

The distance covered during the period of constant speed vmax is;

dv = vmax (tv) ......4

The total distance travelled is

d = da + dv = 100 (Given)

da + dv = 100 ......5

Substituting equation 3 and 4 into 5

0.5vmax(ta) + vmax(tv) = 100

vmax ( 0.5ta +tv) = 100

vmax = 100/(0.5ta + tv) ....6

But,

t = ta + tv

tv = t - ta .......7

Substituting equation 6 into equation 7

vmax = 100/(0.5ta + t - ta)

vmax = 100/(t-0.5ta)

t = 10.06 s

ta = 2.6 s

Substituting the values;

vmax = 100/(10.06 -0.5(2.6))

vmax = 11.42m/s

Note:

ta = acceleration time

tv = constant velocity vmax time

t = overall time

da , dv and d = acceleration, constant velocity and overall distance covered respectively.

8 0

4 years ago

Why are the fingers of a human separated by gaps?

OverLord2011 [107]

A.
It's has to do with the human body forming in the womb. It has a long explanation to it, but I hope just writing A helps.

3 0

3 years ago

Assuming that 70 percent of the Earth’s surface is covered with water at average depth of 0.95 mi, estimate the mass of the wate

Alla [95]

Answer:

The mass of the water on earth is $5.4537\times10^{20}\ kg$

Explanation:

Given that,

Average depth h= 0.95 mi

$h=0.95\times1.609$

$h =1.528\ km$

$h=1.528\times10^{3}\ m$

Radius of earth $r= 6.37\times10^{6}\ m$

Density = 1000 kg/m³

We need to calculate the area of surface

Using formula of area

$A =4\pi r^2$

Put the value into the formula

$A=4\pi\times(6.37\times10^{6})^2$

$A=5.099\times10^{14}\ m^2$

We need to calculate the volume of earth

$V = Area\times height$

Put the value into the formula

$V=5.099\times10^{14}\times1.528\times10^{3}$

$V=7.791\times10^{17}\ m^3$

Now, 70 % volume of the total volume

$V= 7.791\times10^{17}\times\dfrac{70}{100}$

$V=5.4537\times10^{17}\ m^3$

We need to calculate the mass of the water on earth

Using formula of density

$\rho = \dfrac{m}{V}$

$m = \rho\times V$

Put the value into the formula

$m=1000\times5.4537\times10^{17}$

$m =5.4537\times10^{20}\ kg$

Hence, The mass of the water on earth is $5.4537\times10^{20}\ kg$

8 0

4 years ago