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atroni [7]
3 years ago
12

What are the two main types of star clusters?

Physics
1 answer:
julia-pushkina [17]3 years ago
7 0
Fuzzy clustering
Model-based clustering
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You raise a bucket of water from the bottom of a well that is 12 m deep. the mass of the bucket and the water is 5.00 kg, and it
MArishka [77]
Given: Mass m = 5.00 Kg;    Height h = 12 m;    Time t = 15 s

Required: Power P = ?

Formula: P = Fd/t  = mgh/t

               P = (5.0 Kg)(9.8 m/s²)(12 m)/15 s

               P = 39.2 Kg.m²/s²  or
 
               P = 39.2 J





4 0
3 years ago
For which type(s) of signals does noise alter the original information?
nika2105 [10]
Neither analog nor digital
8 0
3 years ago
The period of a 400 hertz sound wave is ___ second
Oksi-84 [34.3K]

Answer:

0.0025 sec

Explanation:

Period = 1 / frequency = 1/400 = 0.0025 sec

3 0
2 years ago
Read 2 more answers
A 0.45 kg ball is moving horizontally with a speed of 5.3 m/s when it strikes a vertical wall. The ball rebounds with a speed of
qaws [65]

Answer:

1.31Kgms-1

Explanation:

∆p = m∆v

Where:

∆p= change in momentum

m= mass of the ball

∆v= change in velocity of the ball= (5.3-2.4)= 2.9ms-1

Therefore, substituting appropriately with the values above:

∆p= 0.45×2.9= 1.31Kgms-1

6 0
4 years ago
Read 2 more answers
a flashlight bulb with a potential difference of 6.0 v across it has a resistance of 8.0 how much current is the bulb filament
Andreas93 [3]

Answer:

<em>I = 0.75 Amp</em>

Explanation:

<u>Ohm's Law</u>

Ohm's law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points. The constant of proportionality is called the Resistance (R) of the conductor.

The formula can be expressed as:

V = I.R

The intensity of the current through a resistor can be calculated by solving the equation for I:

\displaystyle I=\frac{V}{R}

A flashlight bulb is an example of a resistor with the specific task to emit light when it's hot enough.

The potential difference (or voltage) is V=6 V and the resistance is R=8Ω, thus the current is:

\displaystyle I=\frac{6~V}{8~\Omega}

I = 0.75 Amp

3 0
3 years ago
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