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Mumz [18]
3 years ago
15

Can you please expand and simplify (x+4) (x-2) ?

Mathematics
2 answers:
Komok [63]3 years ago
8 0
X^2+2x-8 is the answer
Shtirlitz [24]3 years ago
8 0
So you would use "foil method". answer would be x squared (x^2) + 2x -8
<span>x^2+2x-8</span>
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What are whole number dimensions?
Sphinxa [80]
When you get to the point where the width is larger than the length, you can stop because you have exhausted all the possibilities. The greatest area will be the rectangle that is closer in to a square than any of the others.
5 0
3 years ago
Read 2 more answers
Hii I just wasn't sure about how to answer this so could someone help?
balandron [24]

Answer:

1/2

Step-by-step explanation:

4 0
3 years ago
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Help me please please
ratelena [41]
When dividing same numbers with different exponents (they’re both 10 so this works different than if they were different numbers) you subtract the top exponent by the bottom exponent. So 15-4=11 ultimately making the solution 10^11. Hope this helps :)
4 0
2 years ago
Choose yes or no for each question will mark brainlist :) !!
Serga [27]

Answer:

1. No

2. Yes

3. No

4. Yes

Step-by-step explanation:

Hope this helped!

4 0
3 years ago
A piece of wire 11 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
forsale [732]

Answer:

11 meters

Step-by-step explanation:

First, we can say that the square has a side length of x. The perimeter of the square is 4x, and that is how much wire goes into the square. To maximize the area, we should use all the wire possible, so the remaining wire goes into the triangle, or (11-4x).

The area of the square is x², and the area of an equilateral triangle with side length a is (√3/4)a². Next, 11-4x is equal to the perimeter of the triangle, and since it is equilateral, each side has (11-4x)/3 length. Plugging that in for a, we get the area of the equilateral triangle is

(√3/4)((11-4x)/3)²

= (√3/4)(11/3 - 4x/3)²

= (√3/4)(121/9  - 88x/9 + 16x²/9)

= (16√3/36)x² - (88√3/36)x + (121√3/36)

The total area is then

(16√3/36)x² - (88√3/36)x + (121√3/36) + x²

= (16√3/36 + 1)x² -  (88√3/36)x + (121√3/36)

Because the coefficient for x² is positive, the parabola would open up and the derivative of the parabola would be the local minimum. Therefore, to find the maximum area, we need to go to the absolute minimum/maximum points of x (x=0 or x=2.75)

When x=0, each side of the triangle is 11/3 meters long and its area is

(√3/4)a² ≈ 5.82

When x=2.75, each side of the square is 2.75 meters long and its area is

2.75² = 7.5625

Therefore, a maximum is reached when x=2.75, or the wire used for the square is 2.75 * 4 = 11 meters

3 0
3 years ago
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