Answer:
The force applied on the big piston is 1306.67 N
Explanation:
Given;
force applied on small piston, F₁ = 200 N
diameter of the small piston, d₁ = 4.37 cm
radius of the small piston, r₁ = d₁/2 = 2.185 cm
Area of the small piston, A₁ = πr₁² = π(2.185 cm)² = 15 cm²
Area of the big piston, A₂ = 98 cm²
The pressure of the piston is given by;
Where;
F₂ is the force on big piston
Therefore, the force applied on the big piston is 1306.67 N
Answer:
5.38035 m
Explanation:
= Refactive index of water = 1.43
h = Depth = 5.5 m
Critical angle is given by
d = horizontal distance from the post where she no longer see the bottom of wooden post
So,
The distance d is 5.38035 m
If the distance between two objects decrease and the masses of the objects remain the same, then the force of gravity between the two objects
<u>Answer:</u>
increases
Explanation:
The formula of gravitational force is given as:
F=G Mm/r^2
G = gravitational constant
M, m = Masses of two different objects in which the force is acting.
r = distance between both the objects.
As we can see from the formula that the force of gravity is inversely proportional to the square of the distance between both objects.
When the distance between both objects with the same masses decreases the gravitational force between them increases. Hence the correct answer is option B.
Illamends had the exact same answer from a similar question. Credit goes to her
Answer:
P=F/A where F is the weight of the water and A is the area on which it is resting. The weight of the water is mg. The mass of the water is dv where d is the density and v is the volume. Finally, the volume of the water in a vessel is equal to the area of the base of the vessel times the height of the vessel. (v=Ah)
Plugging everything in we get:
P = dAhg/A
So
P=dhg
So we have shown that liquid pressure is directly proportional to height of liquid in a vessel.
Answer
given,
Time period= T = 1.5 s
If it's moving through equilibrium point at t₀= 0 with v = 1.0 m/s
v_max=1.00 m/s
we know,
v_ max=A ω
v = A sin (ωt)
-0.50= -1.00 sin (ωt)
sin (ωt) = 0.5
t = 0.125 s
we have time period T=1.5 it is the time to complete one oscillation
means from eq to right,then left,then eq,then left,then from right to eq
time taken for left = t/4 = 0.125/4 = 0.375 s
smallest value of time
=0.375 + 0.125
= 0.50 sec
