Answer:
Explanation:
To calculate an effect size, called Cohen's d , for the one-sample t-test you need to divide the mean difference by the standard deviation of the difference, as shown below. Note that, here: sd(x-mu) = sd(x) . μ is the theoretical mean against which the mean of our sample is compared (default value is mu = 0).
Either 175 N or 157 N depending upon how the value of 48° was measured from.
You didn't mention if the angle of 48° is from the lug wrench itself, or if it's from the normal to the lug wrench. So I'll solve for both cases and you'll need to select the desired answer.
Since we need a torque of 55 N·m to loosen the nut and our lug wrench is 0.47 m long, that means that we need 55 N·m / 0.47 m = 117 N of usefully applied force in order to loosen the nut. This figure will be used for both possible angles.
Ideally, the force will have a 0° degree difference from the normal and 100% of the force will be usefully applied. Any value greater than 0° will have the exerted force reduced by the cosine of the angle from the normal. Hence the term "cosine loss".
If the angle of 48° is from the normal to the lug wrench, the usefully applied power will be:
U = F*cos(48)
where
U = Useful force
F = Force applied
So solving for F and calculating gives:
U = F*cos(48)
U/cos(48) = F
117 N/0.669130606 = F
174.8537563 N = F
So 175 Newtons of force is required in this situation.
If the 48° is from the lug wrench itself, that means that the force is 90° - 48° = 42° from the normal. So doing the calculation again (this time from where we started plugging in values) we get
U/cos(42) = F
117/0.743144825 = F
157.4390294 = F
Or 157 Newtons is required for this case.
Answer:
Transverse wave
Explanation:
Its because in transverse wave the particle displacement is perpendicular to the direction of wave propagation..hope it helps you...
Answer:
9 meters
Explanation:
Given:
Mass of Avi is, 
Spring constant is, 
Compression in the spring is, 
Let the maximum height reached be 'h' m.
Now, as the spring is compressed, there is elastic potential energy stored in the spring. This elastic potential energy is transferred to Avi in the form of gravitational potential energy.
So, by law of conservation of energy, decrease in elastic potential energy is equal to increase in gravitational potential energy.
Decrease in elastic potential energy is given as:
Now, increase in gravitational potential energy is given as:
Now, increase in gravitational potential energy is equal decrease in elastic potential energy. Therefore,
Therefore, Avi will reach a maximum height of 9 meters.
Answer:
a) Block 1 = 72.9kgm/s
Block 2 = 0kgm/s
b) vf = 1.31m/s
c) ∆KE = 936.36Joules
Explanation:
a) Momentum = mass× velocity
For block 1:
Momentum = 2.7×27
= 72.9kgm/s
For block 2:
Momentum = 53(0) (body is initially at rest)
= 0kgm/s
b) Using the law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses of the block
u1 and u2 are their initial velocity
v is the common velocity
Given m1 = 2.7kg, u1 = 27m/s, m2 = 53kg, u2 = 0m/s (body at rest)
2.7(27)+53(0) = (2.7+53)v
72.9 = 55.7v
V = 72.9/55.7
Vf = 1.31m/s
c) kinetic energy = 1/2mv²
Kinetic energy of block 1 = 1/2×2.7(27)²
= 984.15Joules
Kinetic energy of block 2 before collision = 0kgm/s
Total KE before collision = 984.15Joules
Kinetic energy after collision = 1/2(2.7+53)1.31²
= 1/2×55.7×1.31²
= 47.79Joules
∆KE = 984.15-47.79
∆KE = 936.36Joules
