RMM magnesium bromide=184
184g=1 mol
4.13g will have=4.13*1/184=0.022mols
molarity=0.022/0.845=0.027M
Answer:
Supersaturated solution
Explanation:
Weren't there any options?
Anyways, the best I can think of right now is a supersaturated solution.
Answer:
= 49.674 g NaCl
Explanation:
From the equation;
1 mole of Sodium metal produces 2 moles sodium chloride
This means;
23 g of Na will produce 116.88 g of NaCl
Therefore;
11.5 g will generate;
= (11.5 × 116.88)/23
= 58.44 g of NaCl
But;
Percentage yield = (Actual yield/Theoretical yield)× 100%
85 /100 = Actual yield /58.44 g
Thus;
Actual yield = 0.85 × 58.44
= 49.674 g NaCl
I’m a dude bruv I mean if u into that
Answer:
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