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navik [9.2K]
3 years ago
10

if 50.0 ml of a 1.00 M HCl solution and 45.0 ml of a 1.00 M NaOH solution are combined, which reagent is limiting?

Chemistry
2 answers:
Maurinko [17]3 years ago
7 0

Answer:

The answer to this question would be: NaOH solution  

Limiting reagent is the reagent that totally consumed in the reaction. To answer this question you need to know the equation for the chemical reaction. The equation would be:

HCl + NAOH = H2O + NACl

All of the coefficient in the reaction is 1, which mean 1 HCl will react to 1 NaOH. In this question, the concentration of HCl and NaOH is same so the amount of the molecule can be reflected by the volume. NaOH has lower volume compared to HCl so it is clear that NaOH will be totally consumed in this reaction.

Explanation:

Setler79 [48]3 years ago
3 0
The answer to this question would be: <span>NaOH solution 

Limiting reagent is the reagent that totally consumed in the reaction. To answer this question you need to know the equation for the chemical reaction. The equation would be:
</span><span>HCl + NAOH = H2O + NACl
</span>
All of the coefficient in the reaction is 1, which mean 1 HCl will react to 1 NaOH. In this question, the concentration of HCl and NaOH is same so the amount of the molecule can be reflected by the volume. NaOH has lower volume compared to HCl so it is clear that NaOH will be totally consumed in this reaction. 
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8 0
3 years ago
2Fe(s) +3H2SO4(aq) →Fe2(SO4)3(aq) +3H2(g)When 10.3 g of iron are reacted with 14.8 moles of sulfuric acid, what is the percent y
Elden [556K]

Answer:

1040%

Explanation:

To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:

Percent yield = Actual yield (5.40g) / Theoretical yield * 100

<em>Moles Fe -Molar mass: 55.845g/mol-:</em>

10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.

For a complete reaction of these moles there are necessaries:

0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.

As there are 14.8 moles of the acid, <em>Fe is limiting reasctant.</em>

The moles of H2 produced are:

0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2

The mass is:

0.277 moles H2 * (2.016g/mol) = 0.558g H2

Percent yield is:

5.40g / 0.558g * 100 = 1040%

It is possible the experiment wasn't performed correctly

7 0
3 years ago
Please help me with this question
Inessa05 [86]

From the calculation, the concentration in parts per billion is 6 ppb.

<h3>What is ppb?</h3>

The term ppb refers to the concentration of a substance in parts per billion. We obtain the ppb using the formula;

Mass of solute/ Mass of solution * 10^9

Now, 1L = 1000cm^3 = 1000 g

The concertation in ppb = 6 * 10^-6 g/1000 g * 10^9

= 6 ppb

Learn more about parts per billion:brainly.com/question/9179966

#SPJ1

4 0
2 years ago
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