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Oduvanchick [21]
3 years ago
11

A 1.2–liter tank at a temperature of 27°C contains a mixture of 1.5 moles of oxygen, 1.2 moles of nitrogen, and 1.6 moles of hyd

rogen. What is the total pressure of the mixture inside the tank? (R = 0.08205 L atm/K mol)
Chemistry
2 answers:
natka813 [3]3 years ago
7 0
You can use PV=nRT to figure this out, solving for P. In this case:

V = 1.2 L
n = 1.5 + 1.2 + 1.6 = 4.3 mol (assuming the question is giving moles of molecular O/N/H)
R = 0.08205 L atm/K mol
T = 27C = 300 K

P = nRT/V = 4.3 * 0.08205 * 300 / 1.2 = 88.2 atm
matrenka [14]3 years ago
7 0
Correct answer is 88.23 atmospheres.
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<h3>Answer:</h3>

\displaystyle 0.1 \ mol \ Fe

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<u>Step 1: Define</u>

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<u>Step 2: Identify Conversions</u>

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<u>Step 3: Convert</u>

  1. Set up:                    \displaystyle 6.022 \cdot 10^{22} \ atoms \ Fe(\frac{1 \ mol \ Fe}{6.022 \cdot 10^{23} \ atoms \ Fe})
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