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Oduvanchick [21]
3 years ago
11

A 1.2–liter tank at a temperature of 27°C contains a mixture of 1.5 moles of oxygen, 1.2 moles of nitrogen, and 1.6 moles of hyd

rogen. What is the total pressure of the mixture inside the tank? (R = 0.08205 L atm/K mol)
Chemistry
2 answers:
natka813 [3]3 years ago
7 0
You can use PV=nRT to figure this out, solving for P. In this case:

V = 1.2 L
n = 1.5 + 1.2 + 1.6 = 4.3 mol (assuming the question is giving moles of molecular O/N/H)
R = 0.08205 L atm/K mol
T = 27C = 300 K

P = nRT/V = 4.3 * 0.08205 * 300 / 1.2 = 88.2 atm
matrenka [14]3 years ago
7 0
Correct answer is 88.23 atmospheres.
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The frequency of an x-ray wave is 3.0 x 1012MHz. Its wave speed is 3.0x 108m/s. Calculate the wavelength of the x-ray wave below
jasenka [17]

Answer: The wavelength of the x-ray wave is 10^{-10}m

Explanation:

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light  = ?

c = speed of x-ray= 3.0\times 10^8m/s

\nu = frequency of x-ray = 3.0\times 10^{12}MHz=3.0\times 10^{18}Hz= 3.0\times 10^{18}s^{-1}     (1Hz=1s^{-1})

Putting in the values:

\lambda=\frac{3.0\times 10^8m/s}{3.0\times 10^{18}s^{-1}}=10^{-10}m

Thus the wavelength of the x-ray wave is 10^{-10}m

5 0
3 years ago
An important reaction that takes place in a blast furnace during the production of iron is the formation of iron metal and CO2 f
ladessa [460]

Answer: Mass of Fe_2O_3 required to form 930 kg of iron is 1328 kg

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

For iron:

Given mass of iron = 930 kg = 930000 g  (1kg=1000g)

Molar mass of iron = 56 g/mol

Putting values in equation 1, we get:

\text{Moles of iron}=\frac{930000g}{56g/mol}=16607mol

The chemical equation for the  production of iron  follows:

Fe_2O_3+3CO\rightarrow 2Fe+3CO_2

By Stoichiometry of the reaction:

2 moles of iron are  produced by =  1 mole of Fe_2O_3

So, 16607 moles of iron will be produced by = \frac{1}{2}\times 16607=8303moles of Fe_2O_3

Now, calculating the mass of Fe_2O_3 from equation 1, we get:

Mass of Fe_2O_3 = moles\times {\text {molar mass}}=8303\times 160=1328480g=1328kg

Thus mass of Fe_2O_3 required to form 930 kg of iron is 1328 kg

6 0
3 years ago
I KNOW THE ANS JUST NEED AN EXPLANATION...PLEASE I WILL Mark you the brainiest
Reika [66]
I’m pretty sure it would be D.
5 0
3 years ago
2. How many mi hr is 30km/s?​
dalvyx [7]

The answer is 67 108.0888km/s.

4 0
3 years ago
How many moles of iron(III) hydroxide precipitate will form when 2.7 moles of aqueous sodium hydroxide reacts completely with ex
aalyn [17]

Answer:

0.9 mole of Fe(OH)3.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Fe(NO3)3 + 3NaOH —> Fe(OH)3 + 3NaNO3

Now, we can determine the moles of iron (III) hydroxide formed from the reaction as follow:

From the balanced equation above,

3 moles of NaOH reacted to produce 1 mole of Fe(OH)3.

Therefore, 2.7 moles of NaOH will react to produce = 2.7/3 = 0.9 mole of Fe(OH)3.

Therefore, 0.9 mole of Fe(OH)3 is produced from the reaction.

7 0
3 years ago
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