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Tanzania [10]
2 years ago
8

A balloon with a volume of 2.0 L is filled with a gas at 3 atmospheres. If the pressure is reduced to 0.5 atmospheres without a

change in temperature, what would be the volume of the balloon?
Chemistry
1 answer:
creativ13 [48]2 years ago
6 0

Answer:

V2 = 12 L

Explanation:

<u>Given the following data;</u>

Initial volume = 2L

Initial pressure = 3 atm

Final pressure = 0.5 atm

To find the new volume V2, we would use Boyles' law.

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

P_{1}V_{1} = P_{2}V_{2}

Substituting into the equation, we have;

3 * 2 = 0.5V_{2}

6 = 0.5V_{2}

V_{2} = \frac {6}{0.5}

V_{2} = 12

<em>V2 = 12L</em>

<em>Therefore, the new volume is 12 Liters. </em>

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Use Charles' Law: V1/T1 = V2/T2. We assume the pressure and mass of the helium is constant. The units for temperature must be in Kelvin to use this equation (x °C = x + 273.15 K).

We want to solve for the new volume after the temperature is increased from 25 °C (298.15 K) to 55 °C (328.15 K). Since the volume and temperature of a gas at a constant pressure are directly proportional to each other, we should expect the new volume of the balloon to be greater than the initial 45 L.

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3 years ago
In the laboratory you dissolve 13.9 g of potassium phosphatein a volumetric flask and add water to a total volume of 250mL.
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Answer:

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Concentration of the potassium cation? 0,786 M.

Concentration of the phosphate anion? 0,262 M.

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Molarity is an unit of chemical concentration given in moles of solute (K₃PO₄) per liters of solution.

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The molarity of the solution is:

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I hope it helps!

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