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Olegator [25]
3 years ago
11

Which statement correctly describes two forms of oxygen, O2 and O3?

Chemistry
2 answers:
fgiga [73]3 years ago
7 0
The two forms of oxygen, O2 and O3 is "<span>They have different molecular structures and different properties."</span>
harkovskaia [24]3 years ago
4 0

Answer: Option (4) is the correct answer.

Explanation:

In an O_{2} molecule there are two oxygen atoms and in a O_{3} molecule there are three oxygen atoms.

So, there will be different number of electrons involved in the bonding of atoms for both O_{2} and O_{3} molecules.

Therefore, both of them will have different structure and reactivity.

Thus, we can conclude that the statement they have different molecular structures and different properties, correctly describes two forms of oxygen, O2 and O3.

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An aqueous solution of potassium sulfate (K2SO4) has a freezing point of -2.24
iragen [17]
An aqueous solution of potassium sulfate exhibits colligative properties. Colligative properties are properties that depends on the concentration of a substance in a solution. These properties are freezing point depression, vapor pressure lowering, osmotic pressure and boiling point elevation. For this problem we use the concept of freezing point depression since we are given the freezing point of the solution. Freezing point depression is as:
 
ΔT = -k(f) x m x i
-2.24 - 0 = -1.86 x m x 3
<span>m = 0.4014

Thus, the molality of the solution is 0.4014.</span>
7 0
3 years ago
Determine how many liters 8.65 g of carbon dioxide gas would occupy at the following conditions.
VashaNatasha [74]
1) 6.17 liters

2)2.66 liters
3 0
3 years ago
What volume (in L) will a 32 g sample of butane gas, C4H10(g), occupy at a temperature of 45.0 oC and a pressure of 728 mm Hg?
larisa86 [58]

Answer:

15.0 L

Explanation:

To find the volume, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (mmHg)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (62.36 L*mmHg/mol*K)

-----> T = temperature (K)

To calculate the volume, you need to (1) convert grams C₄H₁₀ to moles (via the molar mass), then (2) convert the temperature from Celsius to Kelvin, and then (3) calculate the volume (via the Ideal Gas Law).

Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)

Molar Mass (C₄H₁₀): 58.124 g/mol

32 grams C₄H₁₀              1 moles
-------------------------  x  -----------------------  = 0.551 moles C₄H₁₀
                                    58.124 grams

P = 728 mmHg                      R = 62.36 L*mmHg/mol*K

V = ? L                                    T = 45.0 °C + 273.15 = 318.15 K

n = 0.551 moles

PV = nRT

(728 mmHg)V = (0.551 moles)(62.36 L*mmHg/mol*K)(318.15 K)

(728 mmHg)V = 10922.7632

V = 15.0 L

6 0
1 year ago
Compute the number of grams(g) of lead in 22.5 moles of lead.
iogann1982 [59]

Answer:

4662 in grams

Explanation:

hope this helps :).

7 0
3 years ago
Help help help I will give brainliest
vampirchik [111]

Answer:

its b alkyne

Explanation:

brinliest po plsss

8 0
3 years ago
Read 2 more answers
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