Answer:HNO3 + NaOH → H2O + NaNO3
Explanation:
Q1)
molarity is defined as the number of moles of solute in 1 L of solution.
the NaCl solution volume is 1.00 L
number of moles NaCl = NaCl mass present / molar mass of NaCl
NaCl moles = 112 g / 58.5 g/mol = 1.91 mol
the number of moles of NaCl in 1.00 L of solution is - 1.91 mol
therefore molarity of NaCl is 1.91 M
Q2)
molality is defined as the number of moles of solute in 1 kg of solvent.
density is mass per volume.
density of the solution is 1.08 g/mL.
therefore mass of the solution is = density x volume
mass = 1.08 g/mL x 1000 mL = 1080 g
since we have to find the moles in 1 kg of solvent
mass of solvent = 1080 g - 112 g = 968 g
number of moles of NaCl in 968 g of solvent - 1.91 mol
therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg
molality of NaCl solution is 1.97 mol/kg
Q3)
mass percentage is the percentage of mass of solute by total mass of the solution
mass percentage of solution = mass of solute / total mass of the solution
mass of solute = 112 g
total mass of solution = 1080 g
mass % of NaCl = 112 g / 1080 g x 100%
therefore mass % of NaCl = 10.4 %
answer is 10.4 %
(A) 14.8 g → 1.48 × 10^7 µg
The prefix µ means “× 10^(-6)”, so 1 µg = 1 × 10^(-6) g
The conversion factor (CF) = 1 µ g/1 × 10^(-6) g
∴ Mass = 14.8 g × [1 µg/1 × 10^(-6) g] = 1.48 × 10^7 µg
(B) 3.72 g → 3.72× 10^(-3) kg
The prefix k means “× 10^3”, so 1 kg = 1 × 10^3 g
CF = 1 kg/1 × 10^3 g
∴ Mass = 3.72 g × [1 kg/1 × 10^3 g] = 3.72× 10^(-3) kg
(C) 7.5 × 10^4 J → 75 kJ
CF = 1 kJ/1 × 10^3 J
∴ Energy = 7.5 × 10^4 J × [1 kJ/1 × 10^3 J] = 3.72× 10^(-3) kJ = 7.5 × 10^1 kJ
= 75 kJ
Through Air sounds travels approximately 343 meters/second. Why the difference? Because the closer together the molecules in a substance are, the faster sound will travel through that medium.
(2) a base because they accept H+ ions. NH3 is the conjugate base of NH4+.