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3 years ago

Which statement correctly describes two forms of oxygen, O2 and O3?

Chemistry

2 answers:

fgiga [73]3 years ago

7 0

The two forms of oxygen, O2 and O3 is "<span>They have different molecular structures and different properties."</span>

harkovskaia [24]3 years ago

4 0

Answer: Option (4) is the correct answer.

Explanation:

In an $O_{2}$ molecule there are two oxygen atoms and in a $O_{3}$ molecule there are three oxygen atoms.

So, there will be different number of electrons involved in the bonding of atoms for both $O_{2}$ and $O_{3}$ molecules.

Therefore, both of them will have different structure and reactivity.

Thus, we can conclude that the statement they have different molecular structures and different properties, correctly describes two forms of oxygen, O2 and O3.

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How do I connect a nuclear transfer pipe to an energy condenser that is connected to a tessoract?

anastassius [24]

Answer:

Yes You use the nuclear transfuser to do that

Explanation:

6 0

2 years ago

Read 2 more answers

If 23.7 g of Al(OH)3(s) are mixed with 29.5 g of H2SO4(s) and the reaction is run, answer the following questions:

expeople1 [14]

Aluminum hydroxide $\text{Al}(\text{OH})_3$ can behave as a base and neutralize sulfuric acid $\text{H}_2\text{SO}_4$ as in the following equation:

$2\;\text{Al}(\text{OH})_3 \; (s) + 3\; \text{H}_2\text{SO}_4 \; (aq) \to \text{Al}_2(\text{SO}_4)_3 \; (aq) + 6 \; \text{H}_2\text{O} \; (l)$ (Balanced)

(a)

$n = m/M$ . Thus the ratio between the number of moles of the two reactants available:

$n(\text{Al}(\text{OH})_3, \text{supplied}) / n(\text{H}_2\text{SO}_4, \text{supplied})\\= [m(\text{Al}(\text{OH})_3)/ M(\text{Al}(\text{OH})_3)] / [n(\text{H}_2\text{SO}_4) / M(\text{H}_2\text{SO}_4)]\\= [23.7 / (26.98 + 3 \times(16.00 + 1.008))]/[29.5 / (2 \times 1.008 + 32.07 + 4 \times 16.00)]\\\approx 1.01$

The value of this ratio required to lead to a complete reaction is derived from coefficients found in the balanced equation:

$n(\text{Al}(\text{OH})_3, \text{theoretical}) / n(\text{H}_2\text{SO}_4, \text{theoretical}) = 2/3 \approx 0.667$

The ratio for the complete reaction is smaller than that of the reactants available, indicating that the species represented on the numerator, $\text{Al}(\text{OH})_3$ , is in excess while the one on the denominator, $\text{H}_2\text{SO}_4$ , serves as the limiting reagent.

(b)

The quantity of water produced is dependent on the amount of limiting reactants available. $29.5 / (2 \times 1.008 + 32.07 + 4 \times 16.00) = 0.301 \; \text{mol}$ of sulfuric acid is supplied in this reaction as the limiting reagent. $6$ moles of water molecules are produced for every $3$ moles of sulfuric acid consumed. The reaction would thus give rise to $0.301 \; \text{mol} \times 6/3 = 0.602 \; \text{mol}$ of water molecules, which have a mass of $0.602 \times (2 \times 1.008 + 16.00) = 10.8 \; \text{g}$ .

(c)

$\text{Percentage Yield}\\= \text{Actual Yield} / \text{Theoretical Yield} \times 100 \; \%\\= 2.21 / 10.8 \times 100 \; \%\\= 20.4 \; \%$

(d)

The quantity of $\text{Al}(\text{OH})_3$ , the reactant in excess, is dependent on the number of moles of this species consumed in the reaction and thus the quantity of the limiting reagent available. The consumption of every $3$ moles of sulfuric acid, the limiting reagent, removes $2$ moles of aluminum hydroxide $\text{Al}(\text{OH})_3$ from the solution. $0.301 \; \text{mol}$ of sulfuric acid is initially available as previously stated such that $0.301 \; \text{mol} \times 2/3 = 0.201 \; \text{mol}$ , or $0.201 \times (26.98 + 3 \time (16.00 + 1.008)) = 15.7 \; \text{g}$ , of $\text{Al}(\text{OH})_3$ would be eventually consumed.

$23.7 - 15.7 = 8.0 \; \text{g}$ of $\text{Al}(\text{OH})_3$ would thus be in excess by the end of the reaction process.

3 0

3 years ago

What is the ph of a 0.10 m solution of ethylamine at 25 oc? the pkb of ethylamine at 25 ºc is 3.25. ethylamine is a weak base?

denis-greek [22]

To determine the pH of a weak base, we use the equation:

pH = 14 + 0.5 log Kb

Therefore,

pH = 14 + 0.5 log 3.25
pH = 14.26

A weak base is a base which does not fully dissociates into ions when in solution. The solution would contain cations, anions and the compound itself. Hope this helps.

5 0

3 years ago

Colligative properties depend most on which of the following?

erma4kov [3.2K]

Answer: -

Thus Colligative properties depend most on concentration of solute particles.

Explanation: -

Colligative properties are the properties of a solution that depends only on the number of particles of the solute present in the solution and not on the identity of the solute.

The number of solute particles present per unit volume in a solution is referred to as the concentration of solute particles.

Thus Colligative properties depend most on concentration of solute particles.

5 0

3 years ago

In a neutralization reaction ____

Olenka [21]

Answer:

neutralization reaction

Explanation: Because Neutralization Reactions. ... from a neutralization reaction

8 0

3 years ago