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Zolol [24]
3 years ago
7

There are 342 g of sucrose in 1.00 mol of sucrose. What is the molar concentration (molarity) of a solution containing 171 g suc

rose in 1.25L solution?
Chemistry
1 answer:
AVprozaik [17]3 years ago
7 0
For the answer to the question above, use these formulas in solving your problem and as a guide.
<span> 
MM = 342 (g/mol) </span>

<span>171 (g) / 342(g/mol) = x mol of sucrose </span>
<span>x moles of sucrose/ 1.25 L =  Molarity of soultion 

</span>I hope I helped you with your problem. Have a beautiful day!
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