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melomori [17]
3 years ago
9

Can you store cuso4 in an aluminum container? explain your reasoning

Chemistry
1 answer:
mash [69]3 years ago
3 0

We can store the copper sulphate solution in alumiun container, if cover on alumiun is present.

<h3>Can you store cuso4 in an aluminum container?</h3>

Aluminium is more reactive than copper so the Aluminium will displace copper sulphate from its solution by reacting with it but if there is cover on the aluminium then the alumium can't react with copper.

So we can store the copper sulphate solution in alumiun container.

Learn more about container here: brainly.com/question/11459708

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Un recipiente cerrado, de 4,25 L, con tapa móvil, contiene H2S(g) a 740 Torr y 50,0°C. Se introduce en ese recipiente N2(g) a te
yulyashka [42]

Answer:

n_{N_2}=6.41mol

Explanation:

¡Hola!

En este caso, teniendo en cuenta la información dada por el problema, inferimos que primero se debe usar la ecuación del gas ideal con el fin de calcular las moles de gas que se encuentran al inicio del experimento:

PV=nRT\\\\n=\frac{RT}{PV} \\\\n=\frac{0.08206\frac{atm*L}{mol*K}*(50.0+273.15)K}{740/760atm*4.25L}\\\\n=6.41mol

Seguidamente, usamos la ley de Avogadro para calcular las moles finales, teniendo el cuenta que el volumen final es el doble del inicial (8.50 L):

n_2=\frac{6.41mol*8.50L}{4.25L}\\\\n_2=12.82mol

Quiere decir que las moles de N2(g) que se agregaron son:

n_{N_2}=12.81mol-6.41mol\\\\n_{N_2}=6.41mol

¡Saludos!

8 0
3 years ago
A cell is a system of parts that work together to carry out basic life processes. An animal is also a system of parts that work
blagie [28]
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At 25 oC, the rate constant for the first-order decomposition of a pesticide solution is 6.40 x 10-3 min-1. If the starting conc
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Answer:

2.11\ * 10^{-2}  is the correct answer to the given question.

Explanation:

Given k=6.40 x 10-3 min-1.

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[\ A\ ]\ = \ [\  A_{0}\ ]  * e \ ^\  {-kt}

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So  [\ A\ ]_{0}= 0.0314 M

Putting this value into the above equation.

0.0314 \ *\ e^{6.40 x 10^{-3} \ *  \ 62.0  }

=0.211 M

This can be written as

=\ 2.11 *\ 10^{-2}

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Explanation:

3 0
3 years ago
Can someone answer 2 for me please?
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Answer:

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