There are several information's already given in the question. Based on the information's provided, the answer can be easily deduced.
V1 = 25 ml
= 25/1000 liter
= 0.025 liter
V2 = 18 ml
= 18/1000 liter
= 0.018 liter
M2 = 1.0 M
M1 = ?
Then
M1V1 = M2V2
M1 = M2V2/V1
= (1 * 0.018)/0.025
= 0.72 M
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your help.
Answer:
2.9 is the initial pH of the analyte solution.
Explanation:
The dissociation constant of acetic acid as per theoretical value = 
The initial concentration of acetic acid = c = 0.0900 M
initially
c 0 0
At equilibrium
(c-x) x x
The expression of dissociation constant :
![K_a=\frac{[Ac^-][H^+]}{[HAc]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BAc%5E-%5D%5BH%5E%2B%5D%7D%7B%5BHAc%5D%7D)
Solving for x:
x = 0.001264 M
![[H^+]=0.001264 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D0.001264%20M)
The pH of the solution :
![pH=-\log[0.001264]=2.898\approx 2.9](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B0.001264%5D%3D2.898%5Capprox%202.9)
2.9 is the initial pH of the analyte solution.
Answer:
C. Degree of ionization
Explanation:
The strength of an acid or a base is determined by how many H+/H3O+ or OH- ions are dissociated in solution. Therefore, it's describing the degree of ionization.
Example: HCl is a strong acid because in water it will pretty much 100% dissociate into H+ and Cl- ions.
Chemical energy is released from the breaking down of glucose.
(On my left) (On my right side)
Na: 1. Na:1
Cl:2. Cl:1
Na:1 x 2 =2
Na:1 x 2=2
Cl: 1 x 2 = 2
Answer:
2Na + Cl2 -> 2NaCl
