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harkovskaia [24]
3 years ago
8

Function 2

Mathematics
1 answer:
balandron [24]3 years ago
5 0

Answer:

Function 2 has larger max value.

Step-by-step explanation:

We know that the graph of Function 1 has the maximum value of 1 at x = 4 by looking at the graph.

But since we don't know what the maximum value of Function 2 is (Because Function 2 isn't given as a graph but rather an equation.) which means that we have to find the maximum value of Function 2.

\large{f(x) =  -  {x}^{2}  + 4x + 1}

It is not necessary to find x-value for a function because we want to know which function has larger maximum value. We will be using the formula below.

\large \boxed{y =  \frac{4ac -  {b}^{2} }{4a} }

As you may know, a max-min value is indeed y-value. From Function 2, we know the value of a, b and c from standard form y = ax²+bx+c

Substitute our a, b and c in the formula.

\large{y =  \frac{4( - 1)(1) -  {(4)}^{2} }{4( - 1)} } \\ \large{y =  \frac{ - 4 - 16}{ - 4} } \\ \large{y =  \frac{ - 20}{ - 4}  = 5}

Since our maximum value or y-value is 5 for Function 2. Since we also know that Function 1 has 1 as maximum value and Function 2 has 5 as maximum value. Therefore, Function 2 has larger maximum value.

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\bf \begin{cases}
(f\circ g)(x)=x^2-6x+8\\\\
(f\circ g)(x)=f(~~g(x)~~)\\\\
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\end{cases}
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\textit{now, one probability is }x^2-1
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