Answer:
a. Heterozygous individuals may pass on their copy of the disease-causing allele to offspring.
Explanation:
Tay-Sachs, which is a recessive lethal disease ---- Let say the recessive lethal diseases is s
∴ it only results when an individual posses two copies of the diseases-causing allele i.e two copies of the disease will be ss.
Now, when two hetrozygous individuals crossed , it is obvious that each can pass on their copy of the disease-causing allele to the offspring.
Let show an illustration for the above statement.
Let the heterozygous individual be Ts, if Ts cross with another Ts;
we will have:
Ts × Ts
T s
T TT Ts
s Ts ss
the offspring are TT,Ts,Ts,ss
We can now see how the Heterozygous individuals pass on their copy of the disease-causing allele to the offspring (Ts).
Answer:
Box 1: AA
Box 2: Aa
Box 3: AA
Explanation:
In order to figure out the pedigree, you first have to do a punnet square- kind of like cross-multiplying. EX: For the first box: Aa x AA
For box one, we know that it is Aa, and not AA, because box 2 has to be AA.
We know that because Aa X Aa would give us some "aa" offspring which we do not see in the last generation (see 2nd pic). The only way to get no "aa" offspring is to have an AA X Aa cross.
The separation of the sister chromatids during the cell division occurs in the anaphase in mitosis and anaphase II in meiosis.
During the anaphase in mitosis, and the anaphase II of the meiosis, the chromosomes aligned at the center of the nucleus separates and the sister chromatids of the chromosomes starts moving towards the opposite poles as the spindle fibers starts contracting.
It is called c) a protien. which proteins are found in pretty much every living thing
