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3 years ago

Find a positive angle less than one rotation that is coterminal with –308°.

Mathematics

2 answers:

Romashka [77]3 years ago

6 0

Answer:

THE ANSWER IS 52

Step-by-step explanation:

ADD 360 TO -308 AND YOU WILL GET 52.

Anna35 [415]3 years ago

5 0

The answer would be -72 cuz -308 + -72 is -360 which is a whole circle

warningggg: if this is a home quiz your taking , don't put my answer down cuz there is a 30% chance my answer is wrongdoing

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Combine like terms to simplify the following expression: 12x + 4y – 3x + 2 – 8y2 + 32

sesenic [268]

Answer: The answer is 9x-8y²+4y+34

Step-by-step explanation: Since the equation is 12x+4y-3x+2-8y^2 + 32

1. combine like terms so- combine 12x-3x= 89x

2. look for other like terms- 2+32= 34

3. since 8y^2 and 4y are not the same you can combine them

4. put them all together- 9x-8y^2+4y+3

That's you answer. Hope this helped

6 0

2 years ago

Read 2 more answers

Solve j ÷ 3 1/2 for j= 9/10<br><br>A) 4 1/5<br>B) 3 3/10<br>C) 9/35

emmasim [6.3K]

The answer is C) 9/35.

5 0

2 years ago

What is the quotient of a-3 over 7 divided by 3-a over 21

stepan [7]

Answer:

=−3

Step-by-step explanation:

=17a+−37−121a+17

=21(a−3)7(−a+3)

=−3

3 0

3 years ago

A cook had 15 eggs to scramble and equally serve 4 people.

dezoksy [38]

The correct answer is C

3 0

3 years ago

Read 2 more answers

Use a half-angle identity to find the exact value

Tatiana [17]

Given:

$\cos 15^{\circ}$

To find:

The exact value of cos 15°.

Solution:

$$\cos 15^{\circ}=\cos\frac{ 30^{\circ}}{2}$

Using half-angle identity:

$$\cos \left(\frac{x}{2}\right)=\sqrt{\frac{1+\cos (x)}{2}}$

$$\cos \frac{30^{\circ}}{2}=\sqrt{\frac{1+\cos \left(30^{\circ}\right)}{2}}$

Using the trigonometric identity: $\cos \left(30^{\circ}\right)=\frac{\sqrt{3}}{2}$

$$=\sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}}$

Let us first solve the fraction in the numerator.

$$=\sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}}$

Using fraction rule: $\frac{\frac{a}{b} }{c}=\frac{a}{b \cdot c}$

$$=\sqrt{\frac {2+\sqrt{3}}{4}}$

Apply radical rule: $\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$$=\frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}$

Using $\sqrt{4} =2$ :

$$=\frac{\sqrt{2+\sqrt{3}}}{2}$

$$\cos 15^\circ=\frac{\sqrt{2+\sqrt{3}}}{2}$

5 0

3 years ago