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3 years ago

Find the equation of a line given the point and slope below.

Mathematics

1 answer:

Levart [38]3 years ago

4 0

Step-by-step explanation:

$\frac{y - 6}{x - 3} = - 3$

$- 3(x - 3) = y - 6$

$- 3x + 9 = y - 6$

$y = - 3x + 9 + 6 = - 3x + 15$

Option C

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Which of the following points could be the initial point of vector v if it has a magnitude of 10 an the terminal point (-1,5)?

Eddi Din [679]

Let the initial point of the vector be (x,y). Then the magnitude of the vector v can be written as:

$|v|= \sqrt{ (-1-x)^{2} + (5-y)^{2} }$

The magnitude of vecor v is given to be 10. So we can write:

$10= \sqrt{ (-1-x)^{2} + (5-y)^{2} } \\ \\ 100=(-1-x)^{2} + (5-y)^{2}$

Now from the given options, we have to check which one satisfies the above equation. That point will be the initial point of the vector.

The point in option d, satisfies the equation.

$100=(-1+7)^{2} +(5+3)^{2} \\ \\ 
100=36+64 \\ \\ 
100=100$

Thus, the answer to this question is option D

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2 years ago

Consider the rates 45 mile in 8 minutes and 4 minutes to travel 25 mile. Select the statement(s) that are true. Multiple select

icang [17]

Answer:

F) The rates are not equivalent.

Step-by-step explanation:

Consider the rates 45 mile in 8 minutes and 4 minutes to travel 25 mile. Select the statement(s) that are true. Multiple select question.

We find the unit rates

a) 45 mile in 8 minutes , we find the unit rate in miles per minute

8 minutes = 45 miles

1 minute = x

8 × x = 45 miles × 1 minute

x = 45 miles/8 minutes

x = 5.625 miles/ minute

b) 4 minutes to travel 25 miles. Find the unit rate is minutes per mile

25 miles = 4 minutes

1 mile = x

25miles × x = 4 minutes × 1

x = 4 minutes/25 miles

x = 0.16 minutes/mile

Hence, the correct option is

F) The rates are not equivalent.

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2 years ago

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2 years ago

What is the x 19 + 13x = 32

wel

Answer:

Step-by-step explanation:

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3 years ago

What does product rule of exponents say

LuckyWell [14K]

The rules of exponents are
$( x^{m})( x^{n})=( x^{m+n})$
$\frac{ x^{m} }{ x^{n} } = x^{m-n}$
$x^{ \frac{m}{n} } = \sqrt[n]{ x^{m} }$
$( x^{m} )( y^{m} )=(yx)^{m}$
$( x^{m})^{n}=x^{mn}$
$( \frac{x}{y})^{m}= \frac{x^{m}}{y^{m}}$
$x^{-n}= \frac{1}{x^{n}}$
these are just some basic ones

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2 years ago

Read 2 more answers