Pythagorean Theorem: A^2 + B^2 = C^2
<span>We know A and C, let's find B by doing it backwards </span>
<span>C^2 - A^2 = B^2 </span>
<span>4^2 - 7 (square root of 7 squared is just 7) = B^2 </span>
<span>16 - 7 = B^2 </span>
<span>9 = B^2 </span>
As far as I can tell, is referring and assuming the ruler doesn't have any fractional values, namely it only has markings with integers.
so in short is asking, what are the two integers that the fractional 5¼ is between?
64 is the answer. I’m pretty sure .
The function f(x) = x2 - 8x + 7 rewritten by completing the square is x² - 8x + 16 = 9.
<h3>Rewrite the function by completing the square?</h3>
Given the function; f(x) = x² - 8x + 7
To rewrite by completing the square.
We simplify the function into a proper form to completing the square.
x² - 8x + 7 = 0
x² - 8x = -7
We create a trinomial square on the left side of the equation that is equal to the square of the half of b.
(b/2)² = (-4)²
Next, we add the term to both side of the equation.
x² - 8x + (-4)² = -7 + (-4)²
x² - 8x + 16 = 9
Therefore, the function f(x) = x2 - 8x + 7 rewritten by completing the square is x² - 8x + 16 = 9.
Learn more about completing the square method here: brainly.com/question/12356597
#SPJ1
