I believe if b were to equal the value of 0, there would be 2 solutions to the function. Or not mainly if the resulting expression turns out to be a difference of squares.
Eg. f(x) = 2x^2 + 0x + 2
2x^2 + 2
2(x^2 + 1)
Here there would not be x intercepts, mainly because x cannot be solved.
Answer:
Your Answer would be 1000 my friend :D
Answer is <span>4/(468-466)
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The first box is "none of these" since it is not a vertical angle, is not an adjacent angles, and is not a linear pair, the second box is vertical angles
There are four quantum numbers: n, l, ml and ms. When the orbital is 4d, the 4 is corresponding to n. Thus, n=4. Then, the d corresponds to l = 2. Now, to find the value for ml, take the values of -l to +l. Therefore,
<em>ml = -2, -1, 0, 1, 2</em>
<em>Then,ms could only be either +1 or -1.</em>
