Answer: Explanation:First, let's call the number of 2 cent coins: tNext, let's call the number of 5 cent coins: fWe can then write to equations from the information in the problem.Equation 1: t+f=40Equation 2: 0.02t+0.05f=1.55Step 1) Solve the first equation for t:t+f=40t+f−f=40−ft+0=40−ft=40−fStep 2) Substitute (40−f) for t in the second equation and solve for f:0.02t+0.05f=1.55 becomes:0.02(40−f)+0.05f=1.55(0.02×40)−(0.02×f)+0.05f=1.550.80−0.02f+0.05f=1.550.80+(−0.02+0.05)f=1.550.80+0.03f=1.550.80−0.80+0.03f=1.55−0.800+0.03f=0.750.03f=0.750.03f0.03=0.750.030.03f0.03=25f=25Step 3) Substitute 25 for f in the solution to the first equation at the end of Step 1 and calculate t:t=40−f becomes:t=40−25t=15The Solution Is:There are:15 two cent coins25 five cent coins
Step-by-step explanation:
Answer:
3/50
Step-by-step explanation:
It's not as hard as you might think! You can just multiply the denominator and numerators separately. So in this case, you just need to do 9*1 and 25*6. This means that the answer is just 9/150, simplify it and you get, 3/50!
Answer:
First you need to divide 1.6 by 2 to get .8 then multiply
.8 x 6 = 4.8
.8 x 8 = 6.4
Then multiply 4.8 by 6.4 and get 30.72
Answer:
The answer on E D G E N U I T Y is 2,5, and symmetrical
Step-by-step explanation:
I just did it and got it right
Hey!!!
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...
side of a diagonal=2 sqrt50
cm......
HOPE IT HELPS YOU '_'
