Answer:
A.
Step-by-step explanation:
Have a nice day/night :)
Step-by-step explanation:
First, we should define supplementary angles.
Supplementary angles are angles that add up to 180 degrees.
Since 1 and 2 are supplementary and we know their values, we just set them equal to 180 degrees
(
4
y
+
7
)
+
(
9
y
+
4
)
=
180
Now just solve for one variable
13
y
+
11
=
180
13
y
=
169
y
=
13
Now the question asks for m<2, which is
9
y
+
4
So we just plug in
9
⋅
13
+
4
=
121
So m<2 is 121
3x^2 -6x + 6 :) hope this is alright
Solving for the polynomial function of least degree with
integral coefficients whose zeros are -5, 3i
We have:
x = -5
Then x + 5 = 0
Therefore one of the factors of the polynomial function is
(x + 5)
Also, we have:
x = 3i
Which can be rewritten as:
x = Sqrt(-9)
Square both sides of the equation:
x^2 = -9
x^2 + 9 = 0
Therefore one of the factors of the polynomial function is (x^2
+ 9)
The polynomial function has factors: (x + 5)(x^2 + 9)
= x(x^2 + 9) + 5(x^2 + 9)
= x^3 + 9x + 5x^2 = 45
Therefore, x^3 + 5x^2 + 9x – 45 = 0
f(x) = x^3 + 5x^2 + 9x – 45
The polynomial function of least degree with integral coefficients
that has the given zeros, -5, 3i is f(x) = x^3 + 5x^2 + 9x – 45
Y - 6 = 10(x - 2) hope this helps :)
