Question

These are the first six terms of a sequence with a1= - 3: - 3, 8, 19, 30, 41, 52, … Find a recursive formula for this sequence that is valid for n>1. Write your answer in simplest form.

Answer 1

Answer:

$a(n+1)=a(n)+11$

Step-by-step explanation:

The difference between two consecutive elements is 11.

$8=-3+11\\19=8+11\\30=19+11\\41=30+11\\52=41+11$

Hence $a(n+1)=a(n)+11$