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Jlenok [28]
3 years ago
13

What could cause a experiment to be less reliable

Chemistry
1 answer:
dedylja [7]3 years ago
6 0
Two unstable elements that will react to almost anything
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PLEASE HELP IT DUE TODAY WILL GIVE 100 BRAINLY POINTS AND BRAINLYEST
inessss [21]

Answer:

1. The energy intensity from the ruler going through the air

2. This one is pretty simple, you can add or take away things. This question is just asking you to list sounds from high pitch, to lowest pitch. Here are mine:

Timer

Microwave

Mouse clicking

Dog Barking

Voice

Typing

Knocking on door

Breathing

Foot Steps

Explanation:

4 0
3 years ago
Why is it important to living things that water is bonded by h bond and not by covalent or ionic one
nexus9112 [7]
Because im pretty sure the molecules would just fall apart like salt which is ionic
8 0
3 years ago
An excited ozone molecule, O3*, in the atmosphere can undergo one of the following reactions,O3* → O3 (1) fluorescenceO3* → O +
Maurinko [17]

Answer:

The simplified expression for the fraction  is  \text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3 }

Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
4 years ago
According to VSEPR theory, the structure of the ammonia molecule, NH3, is
Hatshy [7]

According to VSEPR theory, the structure of the ammonia molecule, NH3, is linear.

So your answer is B) linear



5 0
3 years ago
Why is it logical to assume that the hydrogen ion concentration in an aqueous solution of a strong monoprotic acid equals the mo
Masja [62]
Strong acids are those that dissociate completely into their ions. So the dissociation equation for a strong acid is:
HA → H⁺ + A⁻

It is visible from the equation that the number of moles of hydrogen ions released is equivalent to the number of moles of acid. For a given volume,
[HA] → [H]⁺ + [A]⁻
Thus, the assumption is logical and fairly accurate
6 0
3 years ago
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