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klio [65]
3 years ago
12

In an electrically neutral atom, the number of

Chemistry
2 answers:
Ann [662]3 years ago
6 0
Yes I believe the correct answer is B
IRINA_888 [86]3 years ago
4 0

Answer:

B

Explanation:

because protons have a +1 charge and electrons have a -1 charge, so if an atom is neutral it must have the same amount of protons and neutrons

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Help me, it’s pretty easy science moon stuff !
trasher [3.6K]
Hello :)
Based on the information I received reading the picture, the answer should be “B”

Explanation: if I am wrong I’m very sorry. But that should be the answer
8 0
3 years ago
Read 2 more answers
C.) Is heating of cobalt (ii) chloride crystals a chemical change or a physical change (Imk)​
miv72 [106K]

Answer: Heating the hydrated forms of cobalt chloride reverses the reactions above, returning cobalt chloride to the blue, water-free, or anhydrous, state. Water is "liberated" in these reactions, known as dehydration reactions.

Explanation:

8 0
3 years ago
Convert 500 inches to m. <br> 1000mm =1m<br> 1inch = 2.54 cm <br> 10mm=1cm
stira [4]

Answer:

12.7m

Explanation:

FORMULA  

for an approximate result, divide the length value by 39.370078

3 0
3 years ago
A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,
choli [55]

Answer:

3.676 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

Knowing that:

V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,

V₂ = ??? L, T₂ = 40°C + 273 = 313 K,

Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.

7 0
3 years ago
In lab you reacted 60 grams of propane (C3H8) with 13 grams of oxygen gas (O2). Your
Andre45 [30]

Answer:

120g

Explanation:

Based on the reaction, when 1 mole of propane and 5 moles of oxygen react, 3 moles of CO2 and 4 moles of H2O are produced. The ratio of production is 3 moles of CO2 per 4 moles of H2O.

Thus, we need to convert mass of water to moles using its molar mass:

Moles H2O (Molar mass: 18g/mol):

63g H2O * (1mol / 18g) = 3.5 moles H2O

Converting to moles of CO2:

3.5 moles H2O * (3 moles CO2 / 4 moles H2O) = 2.625 moles CO2

Mass CO2 (Molar mass: 44g/mol):

2.625 moles CO2 * (44g / mol) = 115.5g of CO2 are released

<h3>120g </h3>

5 0
3 years ago
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