The solution for this problem is:
C6H5NH3Cl is a strong salt: C6H5NH3+ + Cl- C6H5NH3+ + H2O <-----> C6H5NH2 + H3O+
K = Kw/ Kb= 1.0 x 10^-14 / 3.8 x 10^-10= 2.6 x 10^-5
=2.6 x 10^-5 = x^2 / 0.240-x
x = [H3O+] = 0.00251 M
pH = 2.60 is the concentration
It is B. One single bond and one triple bond.
Based on the electronic configuration the elements are classified as metals, non metals and metalloids.
<u>Explanation:</u>
Periodic table consists of three major parts.
The left side consists of metals and the right side consists of non-metals and here Hydrogen element is the exception and in between those two regions we have metalloids, which has the dual character of both metals and non metals.
These elements can be grouped by means of its chemical properties and also due to its outermost electronic configuration.
If the valence shell electrons are same they are categorized under same group.
Answer:
The concentration of dye is 2.29 mg/mL.
Explanation:
According to Beer's law the absorbance (A) of a solution is proportional to its concentration (c). The best fit curve line to an A vs. c plot has a slope of 0.1815 mL/mg and intercept of 0.0477. The resulting equation is:
A = 0.0477 + 0.1815 mL/mg . c
If a solution has an absorbance of 0.464, the concentration of dye will be:
0.464 = 0.0477 + 0.1815 mL/mg . c
c = 2.29 mg/mL
