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Nostrana [21]
3 years ago
13

A student performs the follow experiment.Step 1: she pours a colorless solution into a beaker that contains another colorless li

quid. Yellow particles appear in the liquid Step 2: she lets the yellow particles settle in the beaker and then deprecated the colorless liquid by recantation. Which has most likely occurred in the beaker?
Chemistry
2 answers:
omeli [17]3 years ago
4 0

Answer:

A chemical change in 1 step and a physical change in 2 step.

Explanation:

In the first step, when the student poured colorless solution into the another liquid, yellow particles appeared which means that there is some chemical reaction which has taken place.

In the step 2,  when these yellow colored particles precipitate settled, a colorless liquid at top is left,  so, this is a physical change because no new substance was produced and through the recantation it was removed.

Katen [24]3 years ago
3 0

Answer:

The answer is (A) peeps.

Explanation:

Got a 100% on the quiz

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A mixture of 0.10 mol of NO, 0.050 mol of H2, and 0.10 mol of H2O is placed in a 1.0-L vessel at 300 K. The following equilibriu
tatyana61 [14]

Answer:

[H2] =    0.012 M

[N2] =    0.019 M

[H2O] =  0.057 M

Explanation:

The strategy here is to account for the species at equilibrium given that the concentration of [NO]=0.062M at equilibrium is known and the quantities initially present and its stoichiometry.

                  2NO(g)         +    2H2(g)    ⇒        N2(g)      +         2H2O(g)

i  mol            0.10                   0.050                                             0.10

c mol            -0.038                -0.038                +0019                +0.038                                                

e mol            0.062                 0.012                  00.019               0.057

Since the volume of the vessel is 1.0 L, the concentrations in molarity are:

[NO] =   0.062 M

[H2] =    0.012 M

[N2] =    0.019 M

[H2O] =  0.057 M

5 0
3 years ago
H-1
bonufazy [111]
Answer = B = Neutrons and Mass Number

Isotopes 
are defined as those atoms which have same atomic number but different atomic masses.

Atomic mass is basically the number of protons and neutrons present in an atom.

Atomic number is the number of protons present in an atom.

So, in isotopes the number of protons are same but the number of neutrons vary due to which atomic masses also vary.
In given three isotopes, all have same number of protons but different number of neutrons.
i.e.
H-1 = 1 P + 0 N = 1 u (Proton)
H-2 = 1 P + 1 N = 2 u (Deuterium)
H-3 = 1 P + 2 N = 3 u (Tritium)

Hence, it is clear that the number after H shows a change in number of neutrons and mass number.

7 0
3 years ago
Read 2 more answers
Write the overall, balanced molecular equation and indicate which element is oxidized and which is reduced for the following rea
REY [17]

Explanation:

Mg(s) + Cr(C2H3O2)3 (aq)

Overall, balanced molecular equation

Mg(s) + Cr(C2H3O2)3(aq) --> Mg(C2H3O2)3(aq) + Cr(s)

To identify if an element has been reduced or oxidized, the oxidation number is observed in both the reactant and product phase.

An increase in oxidation number denotes that the element has been oxidized.

A decrease in oxidation number denotes that the element has been reduced.

Oxidation number of Mg:

Reactant - 0

Product - +3

Oxidation number of Cr:

Reactant - +3

Product - 0

Note: C2H3O2 is actually acetate ion; CH3COO- The oxidatioon number of C, H and O do not change.

Oxidized : Mg

Reduced : Cr

7 0
3 years ago
What do you understand by valency electron and valency shell?​
jasenka [17]

Answer:

<h2>total no. of electron present in Valency shell is called valency electron </h2><h2>___________________</h2>

<h2>valency shell is that in which last electron is present</h2>

7 0
3 years ago
Which of the following is not an example of a chemical change?
JulsSmile [24]

Answer:

It is C

Explanation:

It is Cutting paper because cutting paper doesn't alter the chemical composition of paper

5 0
3 years ago
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