I would suggest using a protractor
<span>n = 11<span>.
Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.
Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.
Together, they sold n-10+n-2=2n-12 boxes.
We know that they sold less than n boxes, so our inequality would be
2n-12<n.
To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.
Add 12 to both sides:
n-12+12<0+12; n<12.
This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.
If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>
Factor the polynomial:
4u² – 20u + 25
Rewrite – 20u as – 10u – 10u, and then factor it by grouping:
= 4u² – 10u – 10u + 25
= 2u * (2u – 5) – 5 * (2u – 5)
= (2u – 5) * (2u – 5)
= (2u – 5)² <––– this is the answer.
I hope this helps. =)
Step-by-step explanation:
I hope this helps. good luck
