Answer:
D. Triangle QRS is an isosceles triangle because QR = RS.
Step-by-step explanation:
Find the length of each side of the triangle using the formula for calculating the distance between two points.
D = √(x2-x1)²+(y2-y1)²
For side RS
R(0,0) and S(5, -3.322)
RS = √(5-0)²+(-3.322-0)²
RS = √25+11.035684
RS = √36.035684
RS = 6.0029
For side RQ
R(0,0) and Q(-3, -5.2)
RQ = √(-3-0)²+(-5.2-0)²
RQ = √9+27.04
RQ = √36.04
RQ = 6.0033
For side QS
Q(-3,-5.2) and S(5, -3.322)
QS = √(5+3)²+(-3.322+5.2)²
QS = √64+3.526884
QS = √67.526884
QS = 8.22
From the calculation it can be seen that RS=QR
Since the two sides f the triangle are equal, hence the triangle is an isosceles triangle. An isosceles triangle is a triangle that has two of its sides equal
Answer:
The volume is about 4.24 cm^3.
Step-by-step explanation:
From the question we are told that:
Diameter
Radius 
Height risen
Generally the equation for Volume of a Key is mathematically given by
Since Volume of a cylinder is Given as
Therefore
Correct Option A
The volume is about 4.24 cm^3.
We are choosing 2
2
r
shoes. How many ways are there to avoid a pair? The pairs represented in our sample can be chosen in (2)
(
n
2
r
)
ways. From each chosen pair, we can choose the left shoe or the right shoe. There are 22
2
2
r
ways to do this. So of the (22)
(
2
n
2
r
)
equally likely ways to choose 2
2
r
shoes, (2)22
(
n
2
r
)
2
2
r
are "favourable."
Another way: A perhaps more natural way to attack the problem is to imagine choosing the shoes one at a time. The probability that the second shoe chosen does not match the first is 2−22−1
2
n
−
2
2
n
−
1
. Given that this has happened, the probability the next shoe does not match either of the first two is 2−42−2
2
n
−
4
2
n
−
2
. Given that there is no match so far, the probability the next shoe does not match any of the first three is 2−62−3
2
n
−
6
2
n
−
3
. Continue. We get a product, which looks a little nicer if we start it with the term 22
2
n
2
n
. So an answer is
22⋅2−22−1⋅2−42−2⋅2−62−3⋯2−4+22−2+1.
2
n
2
n
⋅
2
n
−
2
2
n
−
1
⋅
2
n
−
4
2
n
−
2
⋅
2
n
−
6
2
n
−
3
⋯
2
n
−
4
r
+
2
2
n
−
2
r
+
1
.
This can be expressed more compactly in various ways.
X<20-5y (the whole expression divided by 3)
