7 1/12 - 2 3/4
First we have to change mixed numbers to improper fractions
7 1/12 = 7 x 12 + 1 = 85 85/12
2 3/4 = 2 x 4 + 3 = 11 11/4
85/12 - 11/4
Now we need to find the LCD (least common denominator) for 4 and 12
4, 8, 12
12
12 is our LCD, so it becomes our new denominator
85/12 would stay the same because the denominator wasn't changed but for 11/4 our new denominator is 12, so our fraction will change.
11/4 = 33/12
4 goes into 12, 3 times. What you do to the bottom, you do to the top.
3 x 11 = 33
3 x 4 = 12
So, our new fraction is 33/12. Now we subtract
85/12 - 33/12 = 52/12
Now we convert back to a mixed number
52 ÷ 12 = 4 4/12 reduce
4 1/3
Hope this helps.
Answer: Identify the shapes you will need to determine the area of the figure.
Calculate and add the areas of the unshaded triangle and two circles.
Step-by-step explanation:
Answer:
The maximum power generated by the circuit is 300 watts.
Step-by-step explanation:
A quadratic function is one that can be written as an equation of the form:
f (x) = ax² + bx + c
where a, b and c (called terms) are any real numbers and a is nonzero.
In this case, f(x) is P(c) [the power generated], x is the current c (in amperes), a = -12, b = 120 and c = 0.
The vertex is a point that is part of the parabola, which has the value as ordered minimum or maximum function. If the scalar a> 0, the parabola opens or faces up and the vertex is the minimum of the function. In contrast, if a <0, the parabola opens downward and the vertex is the maximum of the function.
The calculation of the vertex, which in this case will be the maximum of the function, is carried out as follows:
- The value of x, in this case the value of current c in amperes, can be calculated with the formula
. In this case:
So c= 5 amperes. The current is 5 amperes. - The value of y, in this case the value of the electric current in watts, is obtained by substituting the value of c previously obtained in the function. In this case: P(5)= -12*5²+120*5. So P(5)= 300 watts
<u><em>The maximum power generated by the circuit is 300 watts.</em></u>
Answer:
4b^2+2b (b^2 means b squared)
Step-by-step explanation: