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3 years ago

Which word does not belong in the group of words Belize, Kingston, Bridgetown, London

Mathematics

2 answers:

Mrrafil [7]3 years ago

6 0

Answer:

Belize

Step-by-step explanation:

i dont know if its right tell me if im wrong

Murljashka [212]3 years ago

5 0

Answer:

belize

Step-by-step explanation:

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A trout lurking 32 cm below the surface of a lake spies an insect flying 17cm above the lake. How many centimeters would the tro

Bumek [7]

Answer:

The Trout will have to jump 49 cm in order to catch the insect

Step-by-step explanation:

Here, we want to calculate the distance the Trout has to jump in order to catch the Insect

To calculate this, we need to know the difference in the distances

From what we have, the Trout is 32 cm below the surface while the Insect is 17 cm above the surface of the lake

The difference in height which will represent the distance that the Trout has to jump to catch the insect will be ;

17 + 32 = 49 cm

3 0

3 years ago

Express the following ratios as fractions in their lowest term

ANTONII [103]

Answer:

1/4 is A and 1/20 is B

Step-by-step explanation:

Not much of an explanation needed

7 0

3 years ago

What is an equation of the line that passes through the point ( 6 , − 2 ) (6,−2) and is perpendicular to the line 6 x + y = 2 6x

Diano4ka-milaya [45]

Answer:

An equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

$y=\frac{1}{6}x-3$

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y=mx+b

where m is the slope and b is the y-intercept.

Given the line

6x+y=2

Simplifying the equation to write into the slope-intercept form

y = -6x+2

So, the slope = -6

As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line.

Thus, the slope of the perpendicular line will be: -1/-6 = 1/6

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 1/6 and the point (6, -2)

$y-\left(-2\right)=\frac{1}{6}\left(x-6\right)$

$y+2=\frac{1}{6}\left(x-6\right)$

subtract 2 from both sides

$y+2-2=\frac{1}{6}\left(x-6\right)-2$

$y=\frac{1}{6}x-3$

Therefore, an equation of the line that passes through the point (6, − 2) and is perpendicular to the line will be:

$y=\frac{1}{6}x-3$

5 0

3 years ago

Given that f(x)=x/2+5,<br> a)find f(2)<br> b)find f^-1(x)<br> c)find f^-1(5)

Aleks04 [339]

A) 6
b) x/f
c) 5/f

Mark brainliest please

Hope this helps you

8 0

2 years ago

Please help if you know the answer

worty [1.4K]

It's C. When you're dividing g(x) by f(x), you get the equations in both B. and C., but C is more correct because you can't have x=-1/3 because the function is undefined at that number (you can't have the denominator equal 0)

3 0

3 years ago

Read 2 more answers