Answer:
3/20=6/40=15/100
Step-by-step explanation:
Multiply 3 by 2 to figure out the numerator for /40 and multiply 20 by 5 to figure out the denominator of 15/
Answer:
C = $137.50
Step-by-step explanation:
Okie dokie, so we already know he charges $50 just for a service call, plus 25 per hour, so let's say the total charge is C.
Now, let's make an equation:
C = 50 + 25(3.5)
Now, multiply 25 and 3.5 together:
C = 50 + 87.5
Now we just combine the like terms:
C = $137.5
Hope this helps :)
Answer: A) .1587
Step-by-step explanation:
Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.
i.e. 
and 
Let x denotes the amount of soda in any can.
Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.
Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =
![P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587](https://tex.z-dn.net/?f=P%28x%3E12.50%29%3D1-P%28x%5Cleq12.50%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B12.50-12.30%7D%7B0.20%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1%29%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.8413%5C%20%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%5C%5C%5C%3D0.1587)
Hence, the required probability= A) 0.1587
The inverse fraction of 15x+14 is f^-1 (x)= x/15-14/15
492.6/48 ~ To simply view this:
480/48 = 10
12.6/48 = 0.25 (roughly).
10.25 would roughly be your answer.
Though...
The actual answer is that:
12.6/48 = 0.2625
So... the answer: 10.2625 would be the answer.
Depending on where you have to estimate to:
10.2625
10.263
10.26
10.3
I hope that helps, have a great of your day! ^ ^
{-Ghostgate-}
