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sattari [20]
2 years ago
15

what is 494949499494949494949494949494949494949494949494949494949494949494949494949494+357308673-72-05743-0376-07640-725-06750-7

534-83-0734-8045734873426094-7623-07236-05740-9734602576230967360347430-37
Mathematics
1 answer:
Naddika [18.5K]2 years ago
6 0

98870645421

Answer:

7353664777899

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Cs<br> R<br> Solve for C<br> t<br> Help me solve for the indicated variable
Masteriza [31]

Answer:

Use the drop-down menus to identify the type of context clue that helped you determine the italicized word’s meaning.

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I made a New Year’s resolution to be generous, but I gave in to avarice instead.

 

The worst result of the hurricane was the inundation of water that flooded streets and basements.

 

Step-by-step explanation:

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3 years ago
Si a es la raíz cuadrada de b ¿también - a será la raíz cuadrada de b?​
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Step-by-step explanation:

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4 0
2 years ago
Write the slope-intercept form of the equation of the line that passes through the point (-4,0 ), and is parallel to y=-(5/4x)+4
amid [387]

Answer:

Step-by-step explanation:

hello :

note :

Use the point-slope formula.

y - y_1 = m(x - x_1)   when : x_1= -4      y_1= 0  

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an equation in the point-slope form is : y +0= -5/4(x+4)

4 0
2 years ago
In a binomial distribution, n = 8 and π=0.36. Find the probabilities of the following events. (Round your answers to 4 decimal p
skelet666 [1.2K]

Answer:

\mathbf{P(X=5) =0.0888}    

P(x ≤ 5 ) = 0.9707

P ( x ≥ 6) = 0.0293

Step-by-step explanation:

The probability of a binomial mass distribution can be expressed with the formula:

\mathtt{P(X=x) =(^{n}_{x} )   \  \pi^x \  (1-\pi)^{n-x}}

\mathtt{P(X=x) =(\dfrac{n!}{x!(n-x)!} )   \  \pi^x \  (1-\pi)^{n-x}}

where;

n = 8 and π = 0.36

For x = 5

The probability \mathtt{P(X=5) =(\dfrac{8!}{5!(8-5)!} )   \  0.36^5 \  (1-0.36)^{8-5}}

\mathtt{P(X=5) =(\dfrac{8!}{5!(3)!} )   \  0.36^5 \  (0.64)^{3}}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 \times 5!}{5!(3)!} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =(\dfrac{8 \times 7 \times 6 }{3 \times 2 \times 1} )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =({8 \times 7 } )  \times  \ 0.0060466 \  \times 0.262144}

\mathtt{P(X=5) =0.0887645}

\mathbf{P(X=5) =0.0888}     to 4 decimal places

b. x ≤ 5

The probability of P ( x ≤ 5)\mathtt{P(x \leq 5) = P(x = 0)+ P(x = 1)+ P(x = 2)+ P(x = 3)+ P(x = 4)+ P(x = 5})

{P(x \leq 5) = ( \dfrac{8!}{0!(8!)} \times  (0.36)^0  \times  (1-0.36)^8  \ )  +  \dfrac{8!}{1!(7!)} \times  (0.36)^1  \times  (1-0.36)^7  \ +\dfrac{8!}{2!(6!)} \times  (0.36)^2  \times  (1-0.36)^6  \ +  \dfrac{8!}{3!(5!)} \times  (0.36)^3  \times  (1-0.36)^5 +  \dfrac{8!}{4!(4!)} \times  (0.36)^4  \times  (1-0.36)^4  \  +  \dfrac{8!}{5!(3!)} \times  (0.36)^5  \times  (1-0.36)^3  \ )

P(x ≤ 5 ) = 0.0281+0.1267+0.2494+0.2805+0.1972+0.0888

P(x ≤ 5 ) = 0.9707

c. x ≥ 6

The probability of P ( x ≥ 6) = 1  - P( x  ≤ 5 )

P ( x ≥ 6) = 1  - 0.9707

P ( x ≥ 6) = 0.0293

4 0
3 years ago
Of the following data, 17, 20,14,5,30,13,6, and 5 find the mean median, and mode
Kazeer [188]
Arrange in ascending order:-

5 5 6 13 14 17 20 30

Mode = 5

Median = mean of middle numbers = (13+14) / 2 = 13.5
6 0
3 years ago
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