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zhuklara [117]
3 years ago
7

A train is moving in uniform velocity and acceleration. A girl inside the train tosses a coin. Where would the coin land?

Physics
1 answer:
Furkat [3]3 years ago
7 0
On the floor because the force from the train moving and she wouldn't be able to catch it in time
You might be interested in
Taking force , length and time as fundamental quantity , find the dimensional formula for density​
Law Incorporation [45]

Answer:

fundamental formula for density = Kg/m³

Explanation:

density = mass/volume

5 0
3 years ago
1. A baseball is thrown horizontally at 45 m/s. The ball slows down at a rate of 5 m/s?
meriva

Answer:

Explanation:

a )

initial velocity u = 45 m/s

acceleration a = - 5 m/s²

final velocity v = 0

v = u - at

0 = 45 - 5 t

t = 9 s

b )

s = ut - 1/2 at²

= 45 x 9 - .5 x5x 9²

405 - 202.5

202.5 m

2 )

a )

s = ut + 1/2 a t²

u = 0

s = 1/2 at²

= .5 x 9.54 x 6.5²

= 201.5 m

b )

v = u + at

= 0 + 9.54 x 6.5

= 62.01 m / s

3

a )

acceleration = (v - u) / t

= (34 - 42) / 2.4

= - 3.33 m /s²

b )

v² = u² - 2 a s

34² = 42² - 2 x 3.33² s

s = 27.41 m

c )

Average velocity

Total displacement / time

= 27.41 / 2.4

= 11.42 m /s

4 )

a )

v = u + at

v = 0 + 3 x 4

= 12 m /s

b )

s = ut + 1/2 a t²

= o + .5 x 3 x 4²

= 24 m

8 0
3 years ago
A car of mass 998 kilograms moving in the positive y–axis at a speed of 20 meters/second collides on ice with another car of mas
goldfiish [28.3K]
    <span> Let’s determine the initial momentum of each car.
#1 = 998 * 20 = 19,960
#2 = 1200 * 17 = 20,400

This is this is total momentum in the x direction before the collision. B is the correct answer. Since momentum is conserved in both directions, this will be total momentum is the x direction after the collision. To prove that this is true, let’s determine the magnitude and direction of the total momentum after the collision.

Since the y axis and the x axis are perpendicular to each other, use the following equation to determine the magnitude of their final momentum.

Final = √(x^2 + y^2) = √(20,400^2 + 19,960^2) = √814,561,600

This is approximately 28,541. To determine the x component, we need to determine the angle of the final momentum. Use the following equation.

Tan θ = y/x = 19,960/20,400 = 499/510
θ = tan^-1 (499/510)

The angle is approximately 43.85˚ counter clockwise from the negative x axis. To determine the x component, multiply the final momentum by the cosine of the angle.

x = √814,561,600 * cos (tan^-1 (499/510) = 20,400</span>
3 0
3 years ago
Two equally charged tiny spheres of mass 1.0 g are placed 2.0 cm apart. When released, they begin to accelerate away from each o
zhannawk [14.2K]

Answer:

The magnitude of the charge on each sphere is 0.135 μC

Explanation:

Given that,

Mass = 1.0

Distance = 2.0 cm

Acceleration = 414 m/s²

We need to calculate the magnitude of charge

Using newton's second law

F= ma

a=\dfrac{F}{m}

Put the value of F

a=\dfrac{kq^2}{mr^2}

Put the value into the formula

414=\dfrac{9\times10^{9}\times q^2}{1.0\times10^{-3}\times(2.0\times10^{-2})^2}

q^2=\dfrac{414\times1.0\times10^{-3}\times(2.0\times10^{-2})^2}{9\times10^{9}}

q^2=1.84\times10^{-14}

q=0.135\times10^{-6}\ C

q=0.135\ \mu C

Hence, The magnitude of the charge on each sphere is 0.135μC.

7 0
3 years ago
Read 2 more answers
state the type of force which provide the needed centripetal force in the following instance :an electron orbiting the nucleus
Vladimir [108]

i think the answer is electrostatic force hope this helps u stay safe

6 0
3 years ago
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