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ad-work [718]
3 years ago
6

1. What is the velocity of an 250-kg that has 6,250 J of energy? Please help

Physics
1 answer:
leonid [27]3 years ago
6 0

Explanation:

KE = 1/2mv^2

6,250 J =1/2(250kg) v ^2

<u>6250 J </u>= <u>125kgv^2</u>

125kg. 125kg

v =

\sqrt{50}

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2 years ago
Explain whether a tennis ball dropped from a high distance experiences an elastic collision or inelastic collision
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I need help on that too poop head
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Holding onto a tow rope moving parallel to a frictionless ski slope, a 70.1 kg skier is pulled up the slope, which is at an angl
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Answer:

given,

mass of the skier = 70.1 Kg

angle with horizontal, θ = 8.6°

magnitude of the force,F = ?

a) Applying newton's second law

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   m g sin\theta - F_{rope} =0

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b) now, when acceleration, a = 0.135 m/s²

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 velocity is constant, a = 0.135 m/s₂

   F_{rope} = m g sin\theta+ma

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3 years ago
A spherical balloon has a radius of 6.55 m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of a
Ksju [112]

Answer:

M_1 = 317.7 kg

Explanation:

Mass of the helium gas filled inside the volume of balloon is given as

m = \rho V

m = 0.179(\frac{4}{3}\pi R^3)

m = 0.179(\frac{4}{3}\pi 6.55^3)

m = 210.7 kg

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M = 210.7 + 990

M = 1200.7 kg

now we know that total weight of balloon + cargo = buoyancy force on the balloon

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<u>Explanation:</u>

An applied force is a force that is applied to an object by an individual or another item. On the off chance that an individual is pushing a work area over the room, at that point there is an applied power following up on the article. The applied power is the power applied on the work area by the individual.

The net force applied to the object rises to the mass of the article increased by the measure of its acceleration. The net power following up on the soccer ball is equivalent to the mass of the soccer ball duplicated by its adjustment in speed each second (its acceleration).

6 0
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