All categories

3 years ago

A car is stationary at first.it moves off with.acceleration of 2m.s-2.Calculate how far it will move in 10s

Physics

1 answer:

Mademuasel [1]3 years ago

3 0

Answer:

100 m.

Explanation:

At first the car was stationary, so its inicial velocity is zero. Considering its inicial position 0 m and using the Equation of motion for the position:

X(t) = Xo + vo.t +a $t^{2}$ /2 , vo=0, Xo=0, a=2m/ $s^{2}$

X(10) = (2 x $10^{2}$ )/2 = 100 m.

You might be interested in

Is electron positive

castortr0y [4]

No the electron is a negative.

The proton is the positive.

Hope this helps!

8 0

3 years ago

Read 2 more answers

Which of the following quantities are unknown?

Novay_Z [31]

Answer:

unknow e and f

Explanation:

In experiments with alpha particles that are obtained by the method of radioactive decay of atoms, some parameters are known

a) Known. The initial velocity is given by the energy of the particles entities by the atomic nuclei

b) Known. The particle charge always 2e, helium core

c) Known. It is set in the given experiment, in general it is selected as zero

d) Known. Placed by the experimenter

e) Unknown. The speed depends on the interactions with the system

f) Unknown. It depends on the interactions with the system, because the position depends on the interactions

g) Known. It is always the value of a helium nucleo

6 0

3 years ago

What is the force of gravity on an object known as?

pshichka [43]

"Gravity force" (also known as "weight")

7 0

4 years ago

When two resistors are wired in series with a 12 V battery, the current through the battery is 0.33 A. When they are wired in pa

Tcecarenko [31]

Answer:

If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

Explanation:

R₁ = Resistance of first resistor

R₂ = Resistance of second resistor

V = Voltage of battery = 12 V

I = Current = 0.33 A (series)

I = Current = 1.6 A (parallel)

In series

$\text{Equivalent resistance}=R_{eq}=R_1+R_2\\\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{0.33}\\\Rightarrow R_1+R_2=36.36\\ Also\ R_1=36.36-R_2$

In parallel

$\text{Equivalent resistance}=\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\Rightarrow {R_{eq}=\frac{R_1R_2}{R_1+R_2}$

$\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{1.6}\\\Rightarrow \frac{R_1R_2}{R_1+R_2}=7.5\\\Rightarrow \frac{R_1R_2}{36.36}=7.5\\\Rightarrow R_1R_2=272.72\\\Rightarrow(36.36-R_2)R_2=272.72\\\Rightarrow R_2^2-36.36R_2+272.72=0$

Solving the above quadratic equation

$\Rightarrow R_2=\frac{36.36\pm \sqrt{36.36^2-4\times 272.72}}{2}$

$\Rightarrow R_2=25.78\ or\ 10.57\\ If\ R_2=25.78\ then\ R_1=36.36-25.78=10.58\ \Omega\\ If\ R_2=10.57\ then\ R_1=36.36-10.57=25.79\Omega$

∴ If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

3 0

3 years ago

Calculate the force required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.

Evgen [1.6K]

Statement:

A force is required to accelerate a 600 g ball from rest to 14 m/s in 0.1 s.

To find out:

The force required to accelerate the ball.

Solution:

Mass of the ball (m) = 600 g = 0.6 Kg
Initial velocity (u) = 0 m/s [it was at rest]
Final velocity (v) = 14 m/s
Time (t) = 0.1 s

Let the acceleration be a.
We know the equation of motion,
v = u + at

Therefore, putting the values in the above formula, we get
14 m/s = 0 m/s + a × 0.1 s
or, 14 m/s ÷ 0.1 s = a
or, a = 140 m/s²

Let the force be F.
We know, the formula : F = ma

Putting the values in the above formula, we get
F = 0.6 Kg × 140 m/s²
or, F = 84 N

Answer:

The force required to accelerate the ball is 84 N and this force acts along the direction of motion.

Hope you could understand.

If you have any query, feel free to ask.

5 0

2 years ago