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3 years ago

Is my answer to part A correct ? And can someone please answer part 2 and if I am wrong correct part A ? !!!!!!

Physics

1 answer:

levacccp [35]3 years ago

5 0

In A, the left side is exactly what you should write, to lead you to the answer ... correct units and everything. But when you tried to walk across the 'equals' sign, you slipped, fell, and got demolished on the rocks below. "19.6" is not the product of the things on the left side. Do the arithmetic again please.

B. When the height doubles, so does the potential energy.

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A charge of 5.0 coulombs moves through a circuit in 0.50 second. What is the current in the circuit

user100 [1]

Answer:

Explanation:

i = 5/.5 = 10 Amps. Hope this helps :)

6 0

3 years ago

How do you find circular motion?

MatroZZZ [7]

Answer:

Explanation:

By multiplying the rotational frequency with the circumference we can determine the average speed of the object. The circular velocity formula is expressed as, vc = 2 πr / T. Where in, r denotes the radius of the circular orbit. T is time period.

6 0

3 years ago

Read 2 more answers

A 45.0-kg person steps on a scale in an elevator. The scale reads 460 n. What is the magnitude of the acceleration of the elevat

WINSTONCH [101]

Answer:

The magnitude of the acceleration of the elevator is 0.422 m/s²

Explanation:

Lets explain how to solve the problem

Due to Newton's Law ∑ Forces in direction of motion is equal to mass

multiplied by the acceleration

We have here two forces 460 N in direction of motion and the weight

of the person in opposite direction of motion

The weight of the person is his mass multiplied by the acceleration of

gravity

→ W = mg , where m is the mass and g is the acceleration of gravity

→ m = 45 kg and g = 9.8 m/s²

Substitute these values in the rule above

→ W = 45 × 9.8 = 441 N

The scale reads 460 N

→ F = 460 N , W = 441 N , m = 45 kg

→ F - W = ma

→ 460 - 441 = 45 a

→ 19 = 45 a

Divide both sides by 45

→ a = 0.422 m/s²

<em>The magnitude of the acceleration of the elevator is 0.422 m/s²</em>

4 0

4 years ago

A m = 94.2 kg object is released from rest at a distance h = 1.15134 R above the Earth’s surface. The acceleration of gravity is

OleMash [197]

Answer:

v= 4055.08m/s

Explanation:

This is a problem that must be addressed through the laws of classical mechanics that concern Potential Gravitational Energy.

We know for definition that,

$U = \frac{GMm}{r}$

We must find the highest point and the lowest point to identify the change in energy, so

Point a)

The problem tells us that an object is dropped at a distance of h = 1.15134R over the earth.

That is to say that the energy of that object is equal to,

$U_1=-\frac{(6.6738 * 10^{-11})(5.98 * 10^{24})(94.2)}{(1.15134)(6.38*10^6)}$

$U_2= - 5.1180*10^9J$

Point B )

We now use the average radius distance from the earth.

$U_2=-\frac{(6.6738 * 10^{-11})(5.98 * 10^{24})(94.2)}{(6.38*10^6)}$

$U_2= -5.8925*10^9J$

Then,

$\Delta U = U_2 - U_1 = -5.1180*10^9J - ( -5.8925*10^9J)$

$\Delta U = 774.5*10^6$

By the law of conservation of energy we know that,

$\Delta U = \frac{1}{2}mv^2$

clearing v,

$v= \sqrt{2 \Delta U/m}$

$v= \sqrt{2*774.5*10^6 /94.2}$

$v= 4055.08m/s$

Therefore the speed of the object when it strikes the Earth’s surface is 4055.08m/s

8 0

3 years ago

The current in a hair dryer measures 11 amps. The resistance of the hair dryer is 12 ohms. What is the voltage?

Valentin [98]

Voltage is given by the formula

V = IR (Ohms law)

where V is the Voltage

I is the current

and R is the Resistance

Here it is given that the current is I=11

Resistance is R =12

so plugging this in the formula

V = IR

V= 11 * 12

V= 132 Volts

So the Voltage for the given dryer is 132 Volts

8 0

4 years ago