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bonufazy [111]
3 years ago
5

Simplify the expression. Write the answer using scientific notation. (2 x 1013)−2

Mathematics
1 answer:
netineya [11]3 years ago
8 0

Answer:

Here's how:

Step-by-step explanation:

1013x2^-4

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Find the measure of the arc BC
ss7ja [257]

Answer:BC is before crist  or the mesuare is 140%

Step-by-step explanation: multiply it by 20

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3 years ago
the farmer's market sells apples for $2 each per pound and oranges doe $1 per pound he sells $56 of apples how many apples does
Effectus [21]

Answer:

28 lb

Step-by-step explanation:

If 1 lb of applies is $2, then 56 / 2 is the number of pounds sold.

3 0
3 years ago
WILL MARK BRAINLIEST, PLEASE HAALLPPP TT^TT
mina [271]

Answer:

here have a nice life

Step-by-step explanation:

1 Lecture 15: Rates of change

1.1 Outline

• Rates of change, velocity, acceleration.

• Marginal rates

• Equation of motion for objects falling under constant gravity

• Interpreting position and velocity graphs

1.2 Rates of change

If f(t) is a function depending on time, then we can write down the average rate of

change on an interval [t1, t2],

f(t2) − f(t1)

t2 − t1

.

We have defined the instantaneous rate of change at a time t as the limit

f

0

(t) = limr→t

f(r) − f(t)

r − t

.

This is also called the derivative. Thus, instantaneous rate of change is another name

for the derivative. In applications the name rate of change is more descriptive.

If s(t) gives the position of a particle as it moves along a line, then

v(t) = limk→0

s(t + k) − s(t)

k

gives the instantaneous velocity. If position is measured in meters and time in seconds,

the velocity v is measured in meters/second. We will abbreviate meters by m and

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4 0
3 years ago
The graph of a line passes through the points (0,2) and (6,0). What is the equation of the line?
Dahasolnce [82]

Answer:

y= -1/3x + 2

Step-by-step explanation:

y=my+p

m=(0-2)/(6-0) = -1/3

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7 0
3 years ago
Read 2 more answers
The small piston of a hydraulic press has an area of 2.0 cm^2 and the large piston has an area of 16 cm^2. If the small piston h
marysya [2.9K]

Answer:

32N

Step-by-step explanation:

Given data

A1= 2cm^2

A2= 16cm^2

F1= 4N

F2=???

Applying the formula

Presure= force/area

P=F/A

F1/A1=F2/A2

substitute

4/2= F2/16

cross multiply

F2= (16*4)/2

F2= 64/2

F2= 32N

Hence the output force is 32N

4 0
3 years ago
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