Question

What is the equation of the line that passes through (5, -2) and (-3, 4)?

Answer 1

First figure out the slope, the equation is Y2-Y1/ X2-X1.. m=-3/4 So far your equation is y=-3/4x + b. b is the y intercept. Plug in either points in the equation to have so far.. you will receive 7/4. The equation is y=-3/4 + 7/4

Answer 2

Answer: $4y=-3x-7$

Step-by-step explanation:

The equation of a line passing through (a,b) and (c,d) is given by :-

$(y-b)=\dfrac{d-b}{c-a}(x-a)$

The equation of a line passing through (5, -2) and (-3, 4) is given by :-

$(y-(-2))=\dfrac{4-(-2)}{-3-5}(x-5)\\\\\Rightarrow\ y+2=\dfrac{6}{-8}(x-5)\\\\\Rightarrow\ y+2=\dfrac{-3}{4}(x-5)\\\\\Rightarrow\ 4(y+2)=-3(x-5)\\\\\Rightarrow\ 4y+8=-3x+15\\\\\Rightarrow\ 4y=-3x-7$