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PSYCHO15rus [73]
3 years ago
5

Are these parallelograms why or why not

Mathematics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

Yes, because they both have two sets of parallel lines.

Hope that helps!

Step-by-step explanation:

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sattari [20]

Answer:

Step-by-step explanation:

10

8 0
1 year ago
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2. Explica que es un cero, o raíz, de una función.​
vovikov84 [41]

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los ceros de una función también se pueden llamar las raíces, básicamente significan donde una función o parábola cruzará la coordenada x. encontrar las raíces de una ecuación significa encontrar donde la parábola intercepta el eje x

Step-by-step explanation:

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3 years ago
An airplane is flying at 180mph. A jet flying at 330 mph leaves 1 hour later traveling in the same direction. How long will it t
zimovet [89]

To solve this problem, let us first assign some variables. Let us say that:

v1 = velocity of airplane = 180 mph

t1 = time travelled by airplane

v2 = velocity of jet = 330 mph

t2 = time travelled by jet

 

Since we know that distance is the product of velocity and time, and that the distance travelled by the two must be equal for the jet to catch up to the plane, hence:

v1 * t1 = v2 * t2

But we know that:

t1 = t2 + 1

Therefore:

180 (t2 + 1) = 330 t2

180 t2 + 180 = 330 t2

150 t2 = 180

t2 = 1.2 hours

 

<span>Therefore the jet can catch up to the plane after 1.2 hours it takes off.</span>

4 0
3 years ago
Which equation shows the result of substituting and expression for y from the first equation into the second equation for the gi
krek1111 [17]

Answer:

x-2x = -3 and x = 3

Step-by-step explanation:

Given the expression

y=x+5.... 1

y-2x=2.... 2

Substituting the first equation into the second we will have;

From 2;

y -2x = 2

x+5-2x = 2

x-2x +5 = 2

x-2x = 2-5

x-2x = -3

-x =-3

x =3

Hence the required equation is x-2x = -3 and x = 3

7 0
2 years ago
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How is the graph of y = (x + 1)^2- 5 transformed from the graph of y=x^2?
Ainat [17]

\text{Hi there! :D}

\boxed{\text{There is a horizontal shift of 1 unit left and 5 units down.}}

\text{Recall that the transformations form of a quadratic function is:}\\\\y = \pm a(b(x-h))+k \text{ where:}\\\\a = \text{ vertical stretch/compression}\\\\b = \text{ horizontal stretch/compression}\\\\h = \text{ shift left/right}\\\\k = \text{ shift up/down}\\\\\text{Therefore, in this instance:}\\\\h = -1\\\\k = -5, \text{ so:}\\\\\text{There is a horizontal shift of 1 unit left and 5 units down.}

8 0
3 years ago
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